Question

The length of a rectangle is 3 yd less than twice the width, and the area of the rectangle is 65yd . find the dimensions of the rectangle.

Answer 1

L=2w-3
65=w(2w-3)
65=2w²-3w
2w²-3w-65=0
2w²+10w
2w(w+5)
-13w-65
-13(w+5)
(2w-13)(w+5)
w=13/2
l=13-3
l=10
The width is 13/2 yd, and the length is 10 yd.