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2 years ago

If the angle of R and the angle of S are vertical angles and the measure of Angle R = 39 degrees, what is the measure of angle S

Mathematics

1 answer:

Marat540 [252]2 years ago

3 0

Answer:

Step-by-step explanation:

Verticle angles are formed when two lines intersect each other, the angles opposite each other are called verticle angles. Verticle angles are congruent, meaning their angle measures are the same. One can apply this knowledge here by stating the following,

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daser333 [38]

subtract 3 from 23 and u will get 20 then divide 2 by 2 and 2 by 20

x= 10

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2 years ago

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How are rate of change and slope related for a linear relationship?

ale4655 [162]

Hello! In slope-intercept form, y=mx+b. M is the slope and b is the y-intercept. The rate of change and slope are interchangeable, therefore, they both create a line through the slope-intercept form. Feel free to rate my answer Brainliest if I helped you!

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3 years ago

To find the measure of ∠A in ∆ABC, use the___(Pythagorean Theorem, Law of Sines, Law of Cosines). To find the length of side HI

nadya68 [22]

Part 1) To find the measure of ∠A in ∆ABC, use

we know that

In the triangle ABC

Applying the law of sines

$\frac{a}{sin\ A}=\frac{b}{sin\ B}=\frac{c}{sin\ C}$

in this problem we have

$\frac{a}{sin\ A}=\frac{b}{sin\ theta}\\ \\a*sin\ theta=b*sin\ A\\ \\ sin\ A=\frac{a*sin\ theta}{b} \\ \\ A=arc\ sin (\frac{a*sin\ theta}{b})$

therefore

the answer Part 1) is

Law of Sines

Part 2) To find the length of side HI in ∆HIG, use

we know that

In the triangle HIG

Applying the law of cosines

$g^{2}=h^{2}+i^{2}-2*h*i*cos\ G$

In this problem we have

g=HI

G=angle Beta

substitute

$HI^{2}=h^{2}+i^{2}-2*h*i*cos\ Beta$

$HI=\sqrt{h^{2}+i^{2}-2*h*i*cos\ Beta}$

therefore

the answer Part 2) is

Law of Cosines

3 0

2 years ago

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A rectangular lawn measures 80 ft by 120 ft. Part of the lawn is torn up to install a sidewalk of uniform width around it. The a

IRISSAK [1]

Answer:

Both answers will give an area of 2400 ft2

but with x=60 we have lawn dimensions -60 ft by -40 ft so this is out

x = 10 ft width for the sidewalk

Check: New lawn dimensions

(80-2x)(60-2x) = 60(40) = 2400 ft^2

Step-by-step explanation:

Draw a diagram:

We have a rectangle inside a rectangle.

The larger outside rectangle is the original lawn: 80ft by 60 ft with area 4800 ft2

The smaller inside rectangle is (80-2x)by(60-2x) where x is width of the new sidewalk.

Area of new lawn is 2400 ft^2

(80-2x)(60-2x) = 2400

4800 - 160x - 120x + 4x2 = 2400

4x2 - 280x + 2400 = 0

Factor out a 4

x2 - 70x + 600 = 0

(x-60)(x-10) = 0

x = 60 ft or x = 10 ft

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2 years ago

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Evaluate the function below for X=3:

Zarrin [17]

Answer:

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Step-by-step explanation:

Step 1: Define

2x³ - x² - 4x + 9

x = 3

Step 2: Evaluate

Substitute in x: 2(3)³ - 3² - 4(3) + 9
Exponents: 2(27) - 9 - 12 + 9
Multiply: 54 - 9 - 12 + 9
Subtract: 45 - 12 + 9
Subtract: 33 + 9
Add: 42

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2 years ago