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suter [353]
3 years ago
14

Enzel goes online to buy a graphing calculator. He finds a site that currently has a promotion of 15% off on all orders over $50

. Enzel decides to buy his graphing calculator, with a price tag of $83, at this site because he knows that he will get the 15% discount when he checks out. Enzel pays 4.5% sales tax on the discounted price and pays a shipping fee of $6.35. What is the total of Enzel’s online purchase?
Mathematics
2 answers:
maw [93]3 years ago
8 0
<h2>Steps</h2>

So firstly, we need to find the discounted price. Since this is going to be a <em>decrease by percentage</em>, we will be using this format:

  • (1 - p)m
  • <em>(p = percentage in decimal form and m = original price)</em>

In this case:

15\% = 0.15\\\\(1-0.15)*83\\0.85*83\\70.55

Now that we have the discounted price, we must apply the 4.5% sales tax. Since this is going to be an <em>increase by percentage</em>, we will be using this format:

  • (1 + p)m

In this case:

4.5\%=0.045\\\\(1+0.045)*73.55\\1.045*70.55\\73.72

Now we have the discounted price with the sales tax. Now all we have to do is add the shipping fee:

73.72+6.35=80.07

<h2>Answer</h2>

<u>The total price of Enzel's purchase is $80.07.</u>

pashok25 [27]3 years ago
3 0

Answer:

A) $80.07

Step-by-step explanation:

for all the lazy ones who don't want to actually learn :)

ED2020

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Dmitry_Shevchenko [17]

Answer:

X = 12

Step-by-step explanation:

Step  1  :

Pulling out like terms :

1.1     Pull out like factors :

  -x - 12  =   -1 • (x + 12)

Equation at the end of step  1  :

Step  2  :

Solving a Single Variable Equation :

2.1      Solve  :    -x-12 = 0

Add  12  to both sides of the equation :

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7 0
3 years ago
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A selective university advertises that 96% of its bachelor’s degree graduates have, on graduation day, a professional job offer
OLEGan [10]

Answer:

The probability is  P( p <  0.9207) = 0.0012556

Step-by-step explanation:

From the question we are told

  The population proportion is p = 0.96

 The sample size is  n  =  227

 The number of graduate who had job is  k = 209

Generally given that the sample size is large enough  (i.e n >  30) then the mean of this sampling distribution is  

       \mu_x = p = 0.96

Generally the standard deviation of this sampling distribution is  

    \sigma  = \sqrt{\frac{p (1 - p )}{n} }

=>  \sigma  = \sqrt{\frac{0.96 (1 - 0.96 )}{227} }

=>  \sigma  = 0.0130

Generally the sample proportion is mathematically represented as

      \^ p =  \frac{k}{n}

=> \^ p =  \frac{209}{227}

=> \^ p =  0.9207

Generally probability of obtaining a sample proportion as low as or lower than this, if the university’s claim is true, is mathematically represented as

     P( p <  0.9207) = P( \frac{\^ p - p }{\sigma } <  \frac{0.9207 - 0.96}{0.0130 }  )

\frac{\^ p - p}{\sigma }  =  Z (The  \ standardized \  value\  of  \ \^ p )

   P( p <  0.9207) = P(Z< -3.022 )

From the z table  the area under the normal curve to the left corresponding to    -3.022  is

     P(Z< -3.022 ) = 0.0012556

=> P( p <  0.9207) = 0.0012556

6 0
3 years ago
Plssss helpp I’ll mark u brainliest fr
garri49 [273]
Answer: it’s the 3’rd one

Explanation: I hope this helps
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3 years ago
A rental company charges a flat fee of $200 plus $50 per day. Create a linear function to represent where f(x) is the total cost
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Y=50x+200

Hope that helps!
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3 years ago
In a string of 12 Christmas tree light bulbs, 3 are defective. The bulbs are selected at random and tested, one at a time, until
Juliette [100K]

Using the hypergeometric distribution, it is found that there is a 0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

In this problem, the bulbs are chosen without replacement, hence the <em>hypergeometric distribution</em> is used to solve this question.

<h3>What is the hypergeometric distribution formula?</h3>

The formula is:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • N is the size of the population.
  • n is the size of the sample.
  • k is the total number of desired outcomes.

In this problem:

  • There are 12 bulbs, hence N = 12.
  • 3 are defective, hence k = 3.

The third defective bulb is the fifth bulb if:

  • Two of the first 4 bulbs are defective, which is P(X = 2) when n = 4.
  • The fifth is defective, with probability of 1/8, as of the eight remaining bulbs, one will be defective.

Hence:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

P(X = 2) = h(2,12,4,3) = \frac{C_{3,2}C_{9,1}}{C_{12,4}} = 0.2182

0.2182 x 1/8 = 0.0273.

0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

More can be learned about the hypergeometric distribution at brainly.com/question/24826394

8 0
2 years ago
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