The partial circles in each corner mean that all 3 angles are identical, which means this is an equatorial triangle. In an equatorial triangle all three sides are the same.
We can set two of the equations to equal each other and solve for x:
3x -5 = 2x +20
Add 5 to each side:
3x = 2x +25
Subtract 2x from each side:
x = 25
For numbers 15-17, we need to remember that two of a triangle's angles are always acute and the third angle will allow us to classify the triangle based on its angles. now that we know this, let's look at #15. the first two angles listed are acute, and the third is an obtuse angle, therefore it is an obtuse triangle. on #16 we have three acute angles, so it is an acute triangle. #17 has two acute angles and a right angle so it is a right triangle.
on numbers 21-23, we need to know that a triangle with all congruent sides is called equilateral, a triangle with two equal sides is isosceles, and a triangle with no equal sides is called scalene. #21 shows two equal sides so it is an isosceles triangle. #22 has three equal sides so it is an equilateral triangle. #23 has no equal sides so it is scalene. hope this helped! :)
Let A = { 0 , 2 , 4 , 6 } , B = { 1 , 2 , 3 , 4 , 5 } , and C = { 1 , 3 , 5 , 7 } . Find { x ∣ x ∈ B or x ∈ C } .
EastWind [94]
Answer:
{1, 2, 3, 4, 5, 7}
Step-by-step explanation:
x in B or C is ...
B ∪ C = {1, 2, 3, 4, 5, 7}
Answer:
Shown
Step-by-step explanation:
Given that twelve basketball players, whose uniforms are numbered 1 through 12, stand around the center ring on the court in an arbitrary arrangement.
Let us consider consecutive numbers in this set.
After this we find the totals are more than 20.
When 1 to 12 are arbitrarily arranged, there are chances that numbers from 6 and above are having consecutive numbers.
These totals are greater than 20
Hence shown that some three consecutive players have the sum of their numbers at least 20.
(i.e. starting from if we take)
Answer:
point form: (2, -2)
equation form: x=2,y=-2
Step-by-step explanation:
