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zzz [600]
3 years ago
14

What is 1/9 - 2 4/9 - 5/9

Mathematics
2 answers:
ANEK [815]3 years ago
4 0

Answer:

10

Step-by-step explanation:

Ymorist [56]3 years ago
3 0
1/9-22/9-5/9
-21/9-5/9
-26/9
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HELP<br><br>Fill in the boxes with fractions are mixed numbers express each answer in simplest form​
Arisa [49]

Answer:

first empty box is 3 and 3/8 i think and second empty box is 4 1/2 correct me if im wrong tho :)

Step-by-step explanation:

6 0
3 years ago
PLEASE HELP AGAIN I NEED THIS EVEN QUICKER
enyata [817]

Answer:

9.5ft is the answer

7 0
3 years ago
Read 2 more answers
Someone please help me it's worth 35 points
Zigmanuir [339]
Question 1)
I assume it asks about the circumference (of only the circle arc)
C=r*2*pi
r=2
-> C=4pi

1 Quarter only of the circle: C/4=pi=3.1

if it's the perimeter of the shape then you need to add the two 2in sides

C=3.1+2*2=7.1

2)
C=r*2*pi, but not a full circle, only semi-> divide by 2-> C=r*pi
r=30
C=30pi=94.2

3)
the radius of the semicircle is 6/2=3mm
semicircle C=r*pi=3pi

add the rectangle perimeter
3pi+2*3+6=12+3pi=21.4

4)
C=2r*pi
insert 2r=d=12
C=12pi=37.7

5)
C=2r*pi
r=10
C=20*pi~62.8

3 rotations of the wheel->
distance=C*3=188.4
4 0
3 years ago
The grizzly bear population in yellowstone national park in 1970 was about 270.Over the next 35 years,it increased by about 115%
yawa3891 [41]

Answer:

581

Step-by-step explanation:

<u>Population of Grizzlys</u>

1970   >>>   270

2005   >>>   115% INCREASE

We need to find 115% of 270 and increase 270 by that amount. Firstly, converting percentage to decimal (division by 100):

115/100 = 1.15

So, that would be now:

1.15 * 270 = 310.5

Increasing, we get:

270 + 310.5 = 580.5

We round to 581

In 2005, the population was about 581

3 0
3 years ago
Researchers at a lake have determined that the percentage of fish in the lake that are intolerant to pollution can be estimated
dusya [7]

Answer:

a. 23.02 %

b. 49%

c. W

Step-by-step explanation:

Solution:-

- A multi-variable function for the percentage of fish in the lake that are intolerant to the pollution is given as:

                     P ( W , R , A ) = 49 - 1.61W - 1.41R - 1.38A

Where,

             W: percentage of wetland

             R: percentage of residential area

             A: percentage of agriculture

- We are to evaluate the percentage of fish intolerant to pollution in the case where W = 3 , R = 15 , A = 0. We will plug in the values in the modeled function P ( W , R , A ) as follows:

                     P ( 3 , 15 , 0 ) = 49 - 1.61*3 - 1.41*15 -1.38*0\\\\P ( 3 , 15 , 0 ) = 23.02\\

- To determine the maximum percentage of fish that will be intolerant to pollution we will employ the use of critical points. The critical point that is defined by the linear relationship between P and all other parameters ( W, R , A ). The maximum value occurs when W = R = A = 0.

                   P ( 0 , 0 , 0 ) = 49 - 1.61*0 -1.41*0 - 1.38*0 = 49

- Hence, the maximum value of the function is 49%.

- The linear relationship between each induvidual parameter ( R, W , A ) and the function ( P ) is proportional in influence. The extent of influence can be quantized by the constant multiplied by each parameter.

- We see that that ( 1.61*W ) > ( 1.41R ) > ( 1.38A ). The greatest influence is by parameter ( W ) i.e the influence of percentage of wetlands .

                   

6 0
3 years ago
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