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dolphi86 [110]
4 years ago
9

Cherries cost $4/lb. Grapes cost $1.50/lb. You can spend no more than $9 on fruit, and you need at least 3 lb in all. Create a g

raph showing the amount of each fruit you can buy.

Mathematics
2 answers:
Natasha2012 [34]4 years ago
8 0

Let

x = lb of Cherries

y = lb of Grapes

4x + 2.50y <= 6

x + y >= 2

Anestetic [448]4 years ago
4 0
Let's say x=cherries and y=grapes. (desmos only does x and y :( ).
the equation would be 9=4x+1.50y

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Work out<br>1/8<br>of 760<br><br>please help​
Mariana [72]

Answer: 95

Step-by-step explanation:

Think of 1/8 times 760 as 760/8 because it’s the same thing.

3 0
3 years ago
Find cos x and cos y! Please help me out! You don’t need to answer all just what you can :)
tangare [24]

Answer:

7. cos(X) = 3/5 = 0.6

cos(Y) = 4/5 = 0.8

8. cos(X) = 15/17 ≈ 0.8824

cos(Y) = 8/17 ≈ 0.4706

9. cos(X) = 1/2 = 0.5

cos(Y) = (√3)/2 ≈ 0.8660

Step-by-step explanation:

The trigonometric ratio for cosine is given as follows;

Cos(\theta) = \dfrac{Adjacent\, side \, to\,  angle}{Hypothenus\, side \, length \ of\, the \  triangle}

7. The adjacent leg length to ∠X = 27

The length of the hypotenuse side of the triangle = 45

∴ cos(X) = 27/45 = 3/5 = 0.6

Cos(X) = 3/5 = 0.6

The adjacent leg length to ∠Y = 36

∴ cos(Y) = 36/45 = 4/5 = 0.8

cos(Y) = 4/5 = 0.8

8. The adjacent leg length to ∠X = 15

The length of the hypotenuse side of the triangle = 17

∴ cos(X) = 15/17 ≈ 0.8824

The adjacent leg length to ∠Y = 8

∴ cos(Y) = 8/17 ≈ 0.4706

9. The adjacent leg length to ∠X = 13

The length of the hypotenuse side of the triangle = 26

∴ cos(X) = 13/26 = 1/2 = 0.5

Cos(X) = 1/2 = 0.5

The adjacent leg length to ∠Y = 13·√3

∴ cos(Y) = 13·√3/26 = (√3)/2 ≈ 0.8660

cos(Y) = (√3)/2 ≈ 0.8660.

4 0
3 years ago
John runs to the market and comes back in 15 minutes. His speed on the way to the market is 5m/s and his speed on the way back i
katen-ka-za [31]

Answer:

The distance to the market is 2000 m

Step-by-step explanation:

∵ John runs to the market and comes back in 15 minutes

→ Change the min. to the sec. because the unit of his speed is m/s

∵ 1 minute = 60 seconds

∴ 15 minutes = 15 × 60 = 900 seconds

→ Assume that t1 is his time to the market and t2 is his time from

  the market

∵  t1 + t2 = 15 minutes

∴ t1 + t2 = 900 ⇒ (1)

→ Assume that the distance to the market is d

∵ His speed on the way to the market is 5m/s

∵ Time = Distance ÷ Speed

∴ t1 = d ÷ 5 ⇒ (1 ÷ 5 = 0.2)

∴ t1 = 0.2d ⇒ (2)

∵ His speed on the way back is 4m/s

∴ t2 = d ÷ 4 ⇒ (1 ÷ 4 = 0.25)

∴ t2 = 0.25d ⇒ (3)

→ Substitute (2) and (3) in (1)

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∴ 0.45d = 900

→ Divide both sides by 0.45

∴ d = 2000 m

∴ The distance to the market = 2000 m

8 0
3 years ago
How do u guys solve this?
enyata [817]
Just graph it in the calculator
6 0
3 years ago
Help please! Ty! Ratios
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Answer:

Ratios to roses to lilies....6:9

Reduced.....2:3

Step-by-step explanation:

Pretty simple doesn't need explaining

8 0
3 years ago
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