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kompoz [17]
2 years ago
11

I WILL Give Brainlist !! ASAP Please Help its A Math Question geometry

Mathematics
1 answer:
Vesna [10]2 years ago
5 0

The diagram which the locus of all the points in the plane that are 3cm away from a single point A is Option B

<h3>What is a locus?</h3>

A locus is defined as a set of points, which satisfies a given condition or situation for a shape or a figure.

It is important to note that:

  • The locus of points in a plane that are all the same distance from a single point is a circle with radius, r
  • A circle is the locus of all the points in the plane which are equidistant from the points in that plane
  • The locus of all points equidistant from the vertices of a square is a straight line that is perpendicular to the plane of the square, through the center of the square

We can see that for a circle, the locus of all points in the plane is the radius equidistant from that line.

Thus, the diagram which the locus of all the points in the plane that are 3cm away from a single point A is Option B

Learn more about locus here:

brainly.com/question/23824483

#SPJ1

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What is the solution to the equation?
12345 [234]
2q+18=-5q-3
2q+5q=-3-18
7q=-21
q=-3
6 0
3 years ago
Pls help me uwuwuwuuwuwuww
Bond [772]

Answer:

128

6

12

48

Step-by-step explanation:

3 0
2 years ago
A system for tracking ships indicated that a ship lies on a hyperbolic path described by 5x2 - y2 = 20. the process is repeated
zysi [14]
Answer:
The ship is located at (3,5)

Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III

Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II

To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.

Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9

We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3

Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5

Based on the above, the position of the ship is (3,5).

Hope this helps :)
8 0
3 years ago
A town has a population of 2000 and grows at 4% every year what will be the population after 15 years to the nearest whole numbe
fomenos

To begin lets say year one the population is 2,000

assume this in percent we can say that 2,000=100%

at the end of this year the population will have grown by 4% meaning that

100%+4% will be the new population =104%

but we know that 100%=2,000 so what about 104%=X?

so (104*2000)/100=2,080

So year 1 the population will have grown by 80 people amounting to 2080 people.

Now do it manually year by year until we reach the 15th year. i will help you up to year 3

2nd year= (2080*104)/100=2163.2

3rd year= (2163*104)/100=2249.728

(If you have more complex questions reach me at essaywritingpool.com)


5 0
3 years ago
Chris has 7/8 yards of purple ribbon and one whole one over 6 yards of ribbon Chris has a total of three holes to over 3 yards o
MaRussiya [10]

Complete question :

Chris has 7/8 yards of purple ribbon and 1 1/6 yards of green ribbon. Chris has a total of 3 2/3 yards of ribbon. How many yards of Chris's ribbon are neither purple nor green.

Answer:

1.625 yards

Step-by-step explanation:

Purple ribbon = 7/8 yards

Green ribbon = 1 1/6 yards = 7/6 yards

Total ribbon = 3 2/3 yards = 11/3 yards

Ribbon that is neither purple nor green :

Total ribbon - (green + purple ribbon)

7/8 - (7/6 + 7/8)

11/3 - (28 + 21) / 24

11/3 - 49/24

= 1.625 yards

8 0
3 years ago
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