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nikitadnepr [17]
4 years ago
7

In a recent golf match, Becky’s score was 5 less than Cathy’s score. Their combined scores totaled 185. Which of the following p

airs of equations can be used to determine their scores? Let b represent Becky’s score and c represent Cathy’s score.
Mathematics
1 answer:
velikii [3]4 years ago
4 0
B=c-5

c+b=185

so, c+(c-5)=185

2c=190
c=95
b=90

As simple as that.
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Is 4 18/12 equal to 5 6/12?
Tom [10]

Answer:

Yes, 4 18/12 is equal to 5 6/12.

Step-by-step explanation:

Given that

4 18/12 = 5 6/12

11/2 = 11/2

Yes both are equal.

7 0
4 years ago
(2x-3)(3x+4) expand and simplify
elixir [45]

Answer:

6x² - x - 12

Step-by-step explanation:

Each term in the second factor is multiplied by each term in the first factor.

(2x - 3)(3x + 4)

= 2x(3x + 4) - 3 (3x + 4) ← distribute both parenthesis

= 6x² + 8x - 9x - 12 ← collect like terms

= 6x² - x - 12 ← in expanded form


5 0
3 years ago
Can someone help me to solve this please? Correct answer only! ^.^​
muminat

Answer: B

Step-by-step explanation:

1. You multiply 4 to both sides, which makes it 1:3.2

2. Multiply 10 to both sides, which makes it 10:32

3. Divide by 2, and the answer is 5:16, which is B.

6 0
3 years ago
Read 2 more answers
Zo0m anyone maybe fnf battle?.
QveST [7]

Answer:

Why would you ask this in the math area?

4 0
3 years ago
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In a study of cell phone usage and brain hemispheric​ dominance, an Internet survey was​ e-mailed to 6965 subjects randomly sele
vladimir1956 [14]

The hypothesis test shows that we reject the null hypothesis and there is sufficient evidence to support the claim that the return rate is less than 20%

<h3>What is the claim that the return rate is less than 20% by using a statistical hypothesis method?</h3>

The claim that the return rate is less than 20% is p < 0.2. From the given information, we can compute our null hypothesis and alternative hypothesis as:

\mathbf{H_o :p =0.2}

\mathbf{H_i:p < 0.2}

Given that:
Sample size (n) = 6965

Sample proportion \mathbf{\hat p = \dfrac{x}{n} = \dfrac{1302}{6965} \sim0.1869}

The test statistics for this data can be computed as:

\mathbf{z = \dfrac{\hat p - p}{\sqrt{\dfrac{p(1-p)}{n}}}}

\mathbf{z = \dfrac{0.1869 -0.2}{\sqrt{\dfrac{0.2(1-0.2)}{6965}}}}

\mathbf{z = \dfrac{-0.0131}{0.0047929}}

z = -2.73

From the hypothesis testing, since the p < alternative hypothesis, then our test is a left-tailed test(one-tailed.

Hence, the p-value for the test statistics can be computed as:

P-value = P(Z ≤ z)

P-value = P(Z ≤ - 2.73)

By using the Excel function =NORMDIST (-2.73)

P-value = 0.00317

P-value ≅ 0.003

Therefore, we can conclude that since P-value is less than the significance level at ∝ = 0.01, we reject the null hypothesis and there is sufficient evidence to support the claim that the return rate is less than 20%

Learn more about hypothesis testing here:

brainly.com/question/15980493

#SPJ1

3 0
2 years ago
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