Two large metal plates of area 1.2 m^2 face each other, 6.5 cm apart, with equal charge magnitudes but opposite signs. The field
1 answer:
Answer:
Q= 722.5 *10⁻¹² C
Explanation:
Conceptual analysis
For a parallel plate capacitor, we can use the following formula :
E= (Q) /(ϵ₀*A) Formula (1)
Where:
E: electric field between the plates ( N/C)
Q: Charge of the plates (C)
ϵo : vacuum permittivity ( C²/ N.m²)
A : area oh the plates (m²)
Known data
A = 1.2 m²
E= 68 N/C
ϵo= 8.8542*10⁻¹² ( C²/ N.m²)
Problem development
We apply the formula (1) :
Q= (68) (8.8542*10⁻¹²)(1.2)
Q= 722.5 *10⁻¹² C
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On substituting the known values,
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<u>Answer:</u>
<em>Thunderbird is 995.157 meters behind the Mercedes</em>
<u>Explanation:</u>
It is given that all the cars were moving at a speed of 71 m/s when the driver of Thunderbird decided to take a pit stop and slows down for 250 m. She spent 5 seconds in the pit stop.
Here final velocity
initial velocity distance
Distance covered in the slowing down phase =
The car is in the pit stop for 5s
After restart it accelerates for 350 m to reach the earlier velocity 71 m/s
total time=
Distance covered by the Mercedes Benz during this time is given by
Distance covered by the Thunderbird during this time=
Difference between distance covered by the Mercedes and Thunderbird
=
Thus the Mercedes is 995.157 m ahead of the Thunderbird.