<span> Beryllium has an exclusive </span>+2<span> oxidation state in all of its compounds</span>
(a) 3000 V
For two parallel conducting plates, the potential difference between the plates is given by:
where
E is the magnitude of the electric field
d is the separation between the plates
Here we have:
is the electric field
d = 4.00 cm = 0.04 m is the distance between the plates
Substituting,
(b) 750 V
The potential difference between the two plates A and B is
Let's take plate A as the plate at 0 volts:
The potential increases linearly going from plate A (0 V) to plate B (3000 V).
So, if the potential difference between A and B, separated by 4 cm, is 3000 V, then the potential difference between A and a point located at 1 cm from A is given by the proportion:
and solving for V(1 cm) we find:
The terminology is somewhat arbitrary, however, In this case, you intentionally alter the angle, which then determines the resulting distance. The presumption of the experiment is that distance is DEPENDENT on the angle. The dependent variable will be the how far the rock went. The dependent variable is the variable that you are testing. The first sentence of description indicates that the experiment is to determine launch Θ vs range.The largest range value is to be determined, so the range is plotted on the Y-axis. Angle Θ is plotted on the X-axis. The distance depends on the launch of the angle so the answer will be (D) how far the rock went. It is the dependent variable.
R2^ 2 / R1 ^2 = g1 / g2 = 38
<span>R2 = R1 x √38 = 6.1644* R1 </span>
<span>R2 = 6.1644 x 6378 000 = 39316632.5 m</span>