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2 years ago

In a belly-flop diving contest, the winner is the diver who makes the biggest splash upon hitting the water. the size

Physics

1 answer:

ad-work [718]2 years ago

7 0

The second diver have to leap to make a competitive splash by 4.08 m high.

<h3>What is potential energy?</h3>

The energy by virtue of its position is called the potential energy.

PE = mgh

where, g = 9.81 m/s²

Given is the diver jumps from a 3.00-m platform. one diver has a mass of 136 kg and simply steps off the platform. another diver has a mass of 100 kg and leaps upward from the platform.

The potential energy of the first diver must be equal to the second diver.

P.E₁ = P.E₂

m₁gh₁ = m₂gh₂

Substitute the vales, we have

136 x 3 = 100 x h₂

h₂ = ₂4.08 m

Thus, the second diver need to leap by 4.08 m high.

Learn more about potential energy.

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What are the change in internal energy if 250 j of hear is added to a system of 80 j of work is done by the system

Sphinxa [80]

Answer:

Explanation:

dU= dq+w

dU is change in internal energy of the system

dq is the amount heat added or released by the system which be positive or negative respectivelý

And w is the amount of work done by the system or on the system which will be positive or negative respectively.

Hence,

dU= 250+80= 330 J

The change will be positive

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4 years ago

What is the definition of evolution

Anna35 [415]

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3 years ago

Read 2 more answers

You are driving at the speed of 27.7 m/s (61.9764 mph) when suddenly the car in front of you (previously traveling at the same s

marta [7]

1) Acceleration of the car in front: -7.89 m/s^2

The only data we need for this part of the problem is:

$u = 27.7 m/s$ --> initial velocity of the car

$\mu=0.804$ --> coefficient of friction between the car wheels and the road

From the coefficient of friction, we can find the deceleration of the car. In fact, the force of friction is given by

$F=-\mu mg$

where m is the car's mass and $g=9.81 m/s^2$ is the acceleration due to gravity. We can find the car's acceleration by using Newton's second law:

$a=\frac{F}{m}=\frac{-\mu mg}{m}=\mu g=(0.804)(9.81 m/s^2)=-7.89 m/s^2$

And the negative sign means it is a deceleration.

2) Braking distance for the car in front: 48.6 m

This can be found by using the following SUVAT equation:

$v^2 - u^2 = 2aS$

where

v=0 is the final velocity of the car

u=27.7 m/s is the initial velocity of the car

a=-7.89 m/s^2 is the acceleration of the car

S is the braking distance

By re-arranging the formula, we find S:

$S=\frac{v^2-u^2}{2a}=\frac{0-(27.7 m/s)^2}{2(-7.89 m/s^2)}=48.6 m$

3) Minimum safe distance at which you can follow the car: 15.0 m

In this case, we must calculate the thinking distance, which is the distance you travel before hitting the brakes. During this time, the speed of your car is constant, so the thinking distance is given by

$d_t = ut=(27.7 m/s)(0.543 s)=15.0 m$

After hitting the brakes, your car decelerates at the same rate of the car in front of you, so the braking distance is the same of the other car:

$d_b=48.6 m$

So the total distance your car covers is

$S'=d_t+d_b=15.0 m +48.6 m=63.6 m$

At the same time, the car in front of you just covered a distance of 48.6 m. So, in order to avoid the collision, you should travel at a distance equal to

$d=S'-S=63.6 m-48.6 m=15.0 m$

6 0

4 years ago

The energy required to dislodge electrons from cesium metal via the photoelectric effect is 207 kJ/mol . What wavelength (in nm)

ki77a [65]

Answer:

So wavelength in nm will be $\lambda =0.956\times 10^{-19}nm$

Explanation:

We have given that the energy = 207 KJ/mol $=207\times 10^3j/mol$

Speed of light $c=3\times 10^8m/sec$

Plank's constant $h=6.6\times 10^{-34}J-s$

According to plank's rule energy of the photon is given by

$E=\frac{hc}{\lambda }$

$207\times 10^3=\frac{6.6\times 10^{-34}\times 3\times 10^8}{\lambda }$

$\lambda =0.956\times 10^{-28}m$

So wavelength in nm will be $\lambda =0.956\times 10^{-19}nm$

6 0

3 years ago

Calculate the frequency of each of the following wave lengths of electromagnetic radiation. Part A 488.0 nm (wavelength of argon

Drupady [299]

Answer:

A. $f=6.1475*10^{14}Hz$

B. $f=5.9642*10^{14}Hz$

Explanation:

The frequency has an inversely proportional relationship with the concept of wavelength, the greater the wavelength, the lower the frequency. For electromagnetic waves, the frequency is equal to the speed of light, divided by the wavelength.

$f=\frac{c}{\lambda}$

$f=\frac{3*10^8\frac{m}{s}}{488*10^{-9}m}\\\\f=6.1475*10^{14}Hz$

$f=\frac{3*10^8\frac{m}{s}}{503*10^{-9}m}\\\\f=5.9642*10^{14}Hz$

7 0

4 years ago