The mass of Jupitar is obtained from the calculations as 5.8 * 10^-14 Kg.
<h3>What is the mass of Jupitar?</h3>
There are nine planets in the solar system and the sun lies at the enter of our solar system. This is the heliocentric model of the solar system.
Given that;
T^2 = GMr^3/4π
T = period
G = gravitational constant
r = radius
M = mass of Jupitar
Now;
1 day = 86400 seconds
1.77 days = 1.77 days * 86400 seconds/1 day
= 152928 seconds
Making M the subject of the formula;
M =4πT^2/Gr^3
M = 4 * 3.142 * (152928)^2/6.67 × 10^-11 * (422 × 10^9)^3
M = 2.9 * 10^11/5.0 * 10^24
M = 5.8 * 10^-14 Kg
Learn more about mass of a planet:brainly.com/question/13851553
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Answer: 50 m/s
Explanation: speed v = 2· pi·n·r = 2· 3.14· 2 s^-1· 4 m
Its true the ionic compounds have a higher melting point
