All categories

3 years ago

What is the equation of the line graphed below?

Mathematics

2 answers:

Verdich [7]3 years ago

8 0

1/2x + y = 3

Solve the equation to put it in slope intercept form. (y=mx+b)

1/2x + y = 3

Subtract 1/2x from both sides.

y = -1/2x + 3

The y-intercept (where the line crosses the y-axis) is three and the slope (rise over run) is -1/2.

Hope this helps!

tangare [24]3 years ago

3 0

Answer: A. $\dfrac{1}{2}x+y=3$

Step-by-step explanation:

The equation of a line passing through two points (a,b) and (c,d) is given by :-

$(y-b)=\dfrac{d-b}{c-a}(x-a)$

Then the equation of a line passing through two points (0,3) and (6,0) is given by :-

$(y-3)=\dfrac{0-3}{6-0}(x-0)\\\\\Rightarrow\ y-3=\dfrac{-1}{2}x\\\\\Rightarrow\ \dfrac{1}{2}x+y=3$

Hence, the equation which is graphed in the given picture :-

$\dfrac{1}{2}x+y=3$

You might be interested in

Please answer it now in two minutes

Gemiola [76]

Answer:

8.4 in

Step-by-step explanation:

Solution:-

- We consider the large right angle triangle namely, " XVW "

- We will recall all the trigonometric ratios that are applicable to all right angled triangles.

- While we are dealing with trigonometric ratios we have the following terms that needs to be correlated with the given specific problem:

Hypotenuse ( H ): Side opposite to 90 degrees angle

Base (B): The side adjacent to the available angle ( θ )

Perpendicular (P): The side opposite to the available angle ( θ )

- We will go ahead and mark our respective sides as follows:

Angle ( θ ) : 34°

Hypotenuse ( H ) : XW = 15 in

Base ( B ) : VW

Perpendicular ( P ) : VX

- Now recall all the trigonometric ratios studied:

sin ( θ ) = P / H = VX / XW

cos ( θ ) = B / H = VW / XW

tan ( θ ) = P / B = VX / VW

- Now choose the appropriate trigonometric ratio with two values given and one ( VX ) that needs to be determined as follows:

sin ( θ ) = P / H = VX / XW

sin ( 34° ) = VX / 15

VX = 15*sin ( 34° )

VX = 8.387 .. ( 8.4 ) in

4 0

3 years ago

In T-ball, the distance to each successive base is 50 feet. If the distance from home plate to the pitcher’s mound is 38 feet, h

JulijaS [17]

Answer:

<h2>The distance from the pitcher's mound and to second base is 37.99 approximately.</h2>

Step-by-step explanation:

The diamond is a square, which in this case has 50 feet long each side, and from home to pitcher is 38 feet. Notice that home is a vertex of the square and the pitcher's mound is the intersection of the diagonals, where they cut half.

We can find the distance from the pitcher to first base using Pythagorean's Theorem, where 50 feet is the hypothenuse.

$50^{2} =38^{2}+x^{2}\\x^{2}=50^{2}-38^{2}\\x=\sqrt{2500-1444}\\ x=\sqrt{1056}\\ x \approx 32.5 \ ft$

Therefore, the distance from the pitcher to first base is 32.5 feet, approximately.

Now, we can use again Pythagorean's Theorem to find the distance from pitcher to second base, where the hypothenuse is 50 feet.

$50^{2}=32.5^{2}+y^{2}\\y^{2}=50^{2}-32.5^{2}\\y=\sqrt{2500-1056.25}\\ y =\sqrt{1443} \approx 37.99$

Therefore, the distance from the pitcher's mound and to second base is 37.99 approximately.

(this results make sense, because the diagonals of a square intersect at half, that means all bases have the same distance from pitcher's mound, so the second way to find the distance asked in the question is just using theory)

8 0

3 years ago

The solution x=6 is a solution to which of the following equations?

Leokris [45]

\left[x \right] = \left[ 6\right][x]=[6] totally answer

8 0

3 years ago

25 POINTS PLZ ANSWER FAST!!!!!!!!!!!!!!!!!!

andrew-mc [135]

Answer:

V = 1/3 ( 35)*12

Step-by-step explanation: