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3 years ago

What is the equation of the line graphed below?

Mathematics

2 answers:

Verdich [7]3 years ago

8 0

1/2x + y = 3

Solve the equation to put it in slope intercept form. (y=mx+b)

1/2x + y = 3

Subtract 1/2x from both sides.

y = -1/2x + 3

The y-intercept (where the line crosses the y-axis) is three and the slope (rise over run) is -1/2.

Hope this helps!

tangare [24]3 years ago

3 0

Answer: A. $\dfrac{1}{2}x+y=3$

Step-by-step explanation:

The equation of a line passing through two points (a,b) and (c,d) is given by :-

$(y-b)=\dfrac{d-b}{c-a}(x-a)$

Then the equation of a line passing through two points (0,3) and (6,0) is given by :-

$(y-3)=\dfrac{0-3}{6-0}(x-0)\\\\\Rightarrow\ y-3=\dfrac{-1}{2}x\\\\\Rightarrow\ \dfrac{1}{2}x+y=3$

Hence, the equation which is graphed in the given picture :-

$\dfrac{1}{2}x+y=3$

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