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3 years ago

What is the equation of the line graphed below?

Mathematics

2 answers:

Verdich [7]3 years ago

8 0

1/2x + y = 3

Solve the equation to put it in slope intercept form. (y=mx+b)

1/2x + y = 3

Subtract 1/2x from both sides.

y = -1/2x + 3

The y-intercept (where the line crosses the y-axis) is three and the slope (rise over run) is -1/2.

Hope this helps!

tangare [24]3 years ago

3 0

Answer: A. $\dfrac{1}{2}x+y=3$

Step-by-step explanation:

The equation of a line passing through two points (a,b) and (c,d) is given by :-

$(y-b)=\dfrac{d-b}{c-a}(x-a)$

Then the equation of a line passing through two points (0,3) and (6,0) is given by :-

$(y-3)=\dfrac{0-3}{6-0}(x-0)\\\\\Rightarrow\ y-3=\dfrac{-1}{2}x\\\\\Rightarrow\ \dfrac{1}{2}x+y=3$

Hence, the equation which is graphed in the given picture :-

$\dfrac{1}{2}x+y=3$

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The measure of angle A is 15°, and the length of side

dangina [55]

Answer:

Part 1) $AB=30.9\ units$

Part 2) $AC=29.9\ units$

Step-by-step explanation:

The picture of the question in the attached figure

Part 1

Find the length side AB

we know that

$sin(A)=\frac{BC}{AB}$ ----> by SOH (opposite side divided by the hypotenuse)

substitute the given values

$sin(15^o)=\frac{8}{AB}$

solve for AB

$AB=\frac{8}{sin(15^o)}=30.9\ units$

Part 2

Find the length side AC

we know that

$tan(A)=\frac{BC}{AC}$ ----> by TOA (opposite side divided by the adjacent side)

substitute the given values

$tan(15^o)=\frac{8}{AC}$

solve for AC

$AC=\frac{8}{tan(15^o)}=29.9\ units$

8 0

2 years ago

What is the value of B?

iragen [17]

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