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ZanzabumX [31]
3 years ago
15

Collin is building a deck on the back of his family‘s house he has enough lumber for the deck to be 144 ft.² the length should b

e 10 feet more than it’s worth what should be the dimensions of the deck
Mathematics
1 answer:
stira [4]3 years ago
6 0
18x8
Use a calculator and plug in numbers
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A high school coach wants to buy new athletic shorts for the 15 members of the basketball team. The coach must spend less than $
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If $200 is the maximum a coach can spend on new shorts, and needs at least 15 shorts, then you could divide or use an inequality. first take the maximum number (200) and the minimum amount (15s) and use the minimum and maximum signs of knowledge to form an inequality. you should end up with 15s<200.
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Can someone plz help me with my geometry pleaseee
gizmo_the_mogwai [7]

Answer:

B'= (0,7)

E'= (3,6)

A'= (5,3)

R'= (2,1)

S'= (-1,4)

Step-by-step explanation:

Add 6 to all x's and add 8 to all y's.

3 0
3 years ago
Devon made a box with length x+1, width x+3, and height x-3. What is the volume of Devon's box as a function of x?
erica [24]

Answer:

(a)

V=x^3+x^2-9x-9

(b)

x=10

(c)

x=\frac{7}{2}

Step-by-step explanation:

we are given

length is x+1

L=x+1

width is x+3

W=x+3

height is x-3

H=x-3

(a)

we can use volume formula

V=L\times W\times H

now, we can plug it

V=(x+1)\times (x+3)\times (x-3)

now, we can simplify it

V=x^3+x^2-9x-9

(b)

we are given volume =1001

so, we can set V=1001

and then we can solve for x

V=x^3+x^2-9x-9=1001

now, we can factor it

\left(x-10\right)\left(x^2+11x+101\right)=0

x-10=0

x=10

(b)

we are given volume

so, we can set

V=14\frac{5}{8}=\frac{14\times 8+5}{8}

V=\frac{117}{8}

and then we can solve for x

V=x^3+x^2-9x-9=\frac{117}{8}

now, we can factor it

8x^3+8x^2-72x-189=0

\left(2x-7\right)\left(4x^2+18x+27\right)=0

2x-7=0

x=\frac{7}{2}

8 0
4 years ago
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