Eureka math lesson 5 5.3

Mathematics

2 answers:

OLEGan [10]4 years ago

6 0

Answer:

A= 1/3-1/4= 7/12

Step-by-step explanation:

1/3=4/12

1/4=3/12

4/12-3/12=7/12

dangina [55]4 years ago

3 0

A is 1/12.

B is 1/6.

C is 7/12.

D is 11/21

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The combined SAT scores for the students at a local high school are normally distributed with a mean of 1504 and a standard devi

SVEN [57.7K]

Answer:

6.68% of students from this school earn scores that satisfy the admission requirement

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 1504, \sigma = 300$

The local college includes a minimum score of 1954 in its admission requirements. What percentage of students from this school earn scores that satisfy the admission requirement

This is 1 subtracted by the pvalue of Z when X = 1954. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{1954 - 1504}{300}$