The computation shows that the placw on the hill where the cannonball land is 3.75m.
<h3>How to illustrate the information?</h3>
To find where on the hill the cannonball lands
So 0.15x = 2 + 0.12x - 0.002x²
Taking the LHS expression to the right and rearranging we have:
-0.002x² + 0.12x -.0.15x + 2 = 0.
So we have -0.002x²- 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x² + 0.03x -2 = 0.
This is a quadratic equation with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25.
The second solution y = 0.15 * 25 = 3.75
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Complete question:
The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?
Its either A or B but my bets are on A
Answer:
x = 2
Step-by-step explanation:
Given
See attachment
Required
What is the value of x?
The vertical axis represents f(x) while the horizontal represents x.
From the attachment:
f(x) = 2 when x = 2
The circled point on attachment 2 represents the required point
<em>Assume that each box is 1 unit.</em>
I would say 5 meals. 7/8 =.875. .875/4=.218. .218+.875=1.09 so the dog would eat 1.09 lb ofdog foodafter 5 meals
Answer:
Step-by-step explanation:
parallel lines
