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poizon [28]
3 years ago
8

Pls help me.........

Mathematics
1 answer:
Natali [406]3 years ago
5 0
Wouldn’t it just be (0,0) ?
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For the straight line defined by the points (4,57) and (6,91) , determine the slope ( m ) and y-intercept ( ???? ). Do not round
Ksivusya [100]

\bf (\stackrel{x_1}{4}~,~\stackrel{y_1}{57})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{91}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{91}-\stackrel{y1}{57}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{4}}}\implies \cfrac{34}{2}\implies 17 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{57}=\stackrel{m}{17}(x-\stackrel{x_1}{4})\implies y-57=17x-68

\bf y=17x-11\impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \qquad \begin{cases} \stackrel{slope}{17}\\\\ \stackrel{y-intercept}{(0,-11)} \end{cases}

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Step-by-step explanation:

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4 years ago
Find the inverse of f(x)=(x−5)/(−4x−2)
uysha [10]

Answer:

{f}^{ - 1} (x)= \frac{  5 - 2x }{ 4x  + 1}

Step-by-step explanation:

The given rational function is

f(x) =  \frac{x - 5}{ - 4x - 2}

Let

y =  \frac{x - 5}{ - 4x - 2}

Interchange x and y

x=  \frac{y- 5}{ - 4y - 2}

Cross multiply

x( - 4y - 2)= y- 5

Expand

- 4xy   - 2x= y- 5  \\ - 4xy  - y=  2x - 5 \\y( - 4x - 1)=  2x - 5

Solve for y;

y= \frac{  2x - 5}{ - 4x - 1}

or

y= \frac{  5 - 2x }{ 4x  + 1}

Therefore

{f}^{ - 1} (x)= \frac{  5 - 2x }{ 4x  + 1}

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