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dusya [7]
3 years ago
8

If j and k are parallel lines, A and B are points on j, and C and D are points on k, how many planes contain points A, B, C, and

D?
A. Exactly one
B. None
C. We can't determine from the given information.
D. Infinitely many

Mathematics
1 answer:
natita [175]3 years ago
8 0

A and B are points on j.

C and D are points on k.

Join AD and BC.

ABCD is a quadrilateral.

Clearly, the quadrilateral ABCD is the only plane that contains the points A, B, C and D.

Hence, correct answer is option A. Exactly one.

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Can someone help me with this i have been trying for hours and i actually got the wrong answer so can you help me understand by
kap26 [50]

Answer:

C

Step-by-step explanation:

We are given that FGH is a triangle, which means that...

Angle F + Angle G + Angle H = 180

Start by substituting the given angle measurements into the equation:

4x+2+13x-7+3x+5=180

Combine like terms

20x=180

Divide both sides by 20 to isolate x

x=9

Plug 9 back in for x to solve for each angle

Angle F = 4(9)+2=36+2=38

Angle G = 13(9)-7=117-7=110

Angle H = 3(9)+5=27+5=32

7 0
2 years ago
Read 2 more answers
Pls help soon:)
Tanzania [10]
Correct answers are:
(1) <span>28, 141 known cases
(2) 79913.71 known cases after six weeks (round off according to the options given)
(3) After approx. 9 weeks (9.0142 in decimal)

Explanations:
(1) Put x = 0 in given equation
</span><span>y= 28, 141 (1.19)^x
</span><span>y= 28, 141 (1.19)^(0)
</span>y= 28, 141


(2) Put x = 6 in the given equation:
<span>y= 28, 141 (1.19)^x
</span><span>y= 28, 141 (1.19)^(6)
</span>y= 79913.71

(3) Since
y= 28, 141 (1.19)^x
And y = <span>135,000

</span>135,000 = 28, 141 (1.19)^x
135,000/28, 141 = (1.19)^x

taking "ln" on both sides:
ln(4.797) = ln(1.19)^x

ln(4.797) = xln(1.19)
x = 9.0142 (in weeks)

5 0
3 years ago
jane passes a signpost saying paris 8km how many miles is she from paris when she passes the signpost
-Dominant- [34]

Answer:

Step-by-step explanation:

3 0
3 years ago
Please answer correctly will mark brainliest, thanks!
monitta
2 first class tickets
4 coach tickets

3 0
3 years ago
The endpoints of (MP)are M(2,1) and P(12,6). If point K partitions (MP) in a ratio of MK:KP = 3:2, what are the coordinates of K
GREYUIT [131]

Answer:

K(8, 4)

Step-by-step explanation:

Given:

M(2, 1), P(12, 6)

MK:KP = 3:2

Required:

Coordinates of K

SOLUTION:

Coordinates of K can be determined using the formula below:

x = \frac{mx_2 + nx_1}{m + n}

y = \frac{my_2 + ny_1}{m + n}

Where,

M(2, 1) = (x_1, y_1)

P(12, 6) = (x_2, y_2)

m = 3, n = 2

Plug in the necessary values to find the coordinates of K:

x = \frac{mx_2 + nx_1}{m + n}

x = \frac{3(12) + 2(2)}{3 + 2}

x = \frac{36 + 4}{5}

x = \frac{40}{5}

x = 8

y = \frac{my_2 + ny_1}{m + n}

y = \frac{3(6) + 2(1)}{3 + 2}

y = \frac{18 + 2}{5}

y = \frac{20}{5}

y = 4

The coordinates of K = (8, 4)

3 0
3 years ago
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