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nalin [4]
3 years ago
7

Use suitable identities to find the following products (x-5) (x-5)​

Mathematics
1 answer:
Marrrta [24]3 years ago
7 0

Step-by-step explanation:

(x - 5)(x - 5) \\  {x}^{2}  - 5x - 5x + 25 \\  {x}^{2}  - 10x + 25

I hope it makes sense

:)

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Hello, precalc, need help on finding csc
Ainat [17]

Recall the double angle identity for cosine:

\cos(2x) = \cos^2(x) - \sin^2(x) = 1 - 2 \sin^2(x)

It follows that

\sin^2(x) = \dfrac{1 - \cos(2x)}2 \implies \sin(x) = \pm \sqrt{\dfrac{1-\cos(2x)}2} \implies \csc(x) = \pm \sqrt{\dfrac2{1-\cos(2x)}}

Since 0° < 22° < 90°, we know that sin(22°) must be positive, so csc(22°) is also positive. Let x = 22°; then the closest answer would be C,

\csc(22^\circ) = \sqrt{\dfrac2{1-\cos(44^\circ)}} = \sqrt{\dfrac2{1-\frac5{13}}} = \dfrac{\sqrt{13}}2

but the problem is that none of these claims are true; cot(32°) ≠ 4/3, cos(44°) ≠ 5/13, and csc(22°) ≠ √13/2...

3 0
2 years ago
The diameter of a cone is X cm the height is 18 cm mThe The height is 18 cm and the volume is 301.44 cm what is x
HACTEHA [7]
The volume of a cone is V=(1/3)(area of the base)(height)= (1/3)(pi*r^2)(h)
r^2= (d/2)^2 = (d^2)/4. Given: V= 301.44cm^3 and h= 18cm.
r^2= V/[(1/3)(pi)(h)]
r^2= 3V/(pi)(h)
(d^2)/4= 3(301.44)/(3.14)(18)
d^2= 12(301.44)/(3.14)(18)
d^2= 63.967
d= 7.997
d~= 8cm.
4 0
3 years ago
Haley's softball team has a phone tree in case a game is cancelled. The coach calls three players. THen each of those players ca
Ksju [112]

Answer:

27

Step-by-step explanation:

If we follow the amount of players called,

Coach called three/3

Players called three/3

Three players called three/3

And make it into a equation, 1 x 3 = 3

Those three people call three more: 3 x 3 = 9

Those nine people call three more: 9 x 3 = 27

6 0
3 years ago
A city garden club is planting a square garden. They drive pegs into the ground at each corner and tie strings between each pair
Dafna1 [17]

Answer:

first blank is "rhombus"

second blank is "rectangle"

third blank is "are congruent"

Step-by-step explanation:

5 0
3 years ago
What is 2 to the power of 4/3 equal to
Reika [66]

Answer:

<h2><u>E</u><u>k</u>sponent</h2>

\sf{ \large{ \boxed{ \red{ {a}^{ \frac{n}{m}  }  =  \sqrt[m]{ {a}^{n} } } } }}

\sf{ {2}^{ \frac{4}{3} } }

=  \sqrt[3]{ {2}^{4} }

=   \sqrt[3]{2 \times 2 \times 2 \times 2}

=   \boxed  {\bold{\sqrt[3]{16}(c.) }}

4 0
2 years ago
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