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Paladinen [302]
3 years ago
7

the length of a rectangle is six times its width. if the area of the rectangle is 294 cm^2, find its perimeter. ​

Mathematics
1 answer:
Genrish500 [490]3 years ago
7 0

Answer:

98 inches

Step-by-step explanation:

6x^2=294

x^2=49

x=7

2*7+2*42=  14+84=98 inches

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Given the third-order differential equation z′′′+2z′′−4z′−8z=0, find the general solution. Enter your solution as z(x)=... . In
Scorpion4ik [409]

Answer: z(x) = c_{1} e^{2x} +c_{2} e^{-2x} + c_{3} xe^{-2x}

Step-by-step explanation:

This is a <em>homogeneous linear third-order differential equation</em>

z′′′+2z′′−4z′−8z=0 so the

FIRST STEP is to find the characteristic equation and its roots

<em>m^{3} +2m^{2} -4m -8 = 0</em>

Using the method of finding roots of a polynomial (using m = 2) would provide the solution below

(m-2)(m+2)(m+2)=0;  m = 2 and m = -2 (repeated twice)

SECOND STEP is to write the general solution with the arbitrary constants.

The general solution based on the roots and the using x as the independent variable would provide

z(x) = c_{1} e^{2x} +c_{2} e^{-2x} + c_{3} xe^{-2x}

<em>*It should be noted that when the characteristic equation has a repeated root, the general equation form becomes similar to the last part of the answer*</em>

6 0
3 years ago
According to the Centers for Disease control and prevention, 20.8 of high school students currently use electronic cigarettes. A
Setler79 [48]

Answer:

H0 : p = 0.028

H1: p > 0.028

We conclude that there is not enough evidence to support the school counselor's claim they the use of electronic cigarettes in high school is higher Than 2.8%

Type 11 error

Step-by-step explanation:

H0 : p = 0.028

H1: p > 0.028

If null should not be rejected then;

We conclude that there is not enough evidence to support the school counselor's claim they the use of electronic cigarettes in high school is higher Than 2.8%

3.)

If the actual proportion is 0.034, which means 3.4%, this means it is actually higher. For failing to reject a false Null, then a type 11 error has been committed

6 0
3 years ago
Please help me!!!!!!!!!!!!!​
monitta

Answer:  see proof below

<u>Step-by-step explanation:</u>

Use the following Half-Angle Identities:    tan (A/2) = (sinA)/(1 + cosA)

                                                                     cot (A/2) = (sinA)/(1 - cosA)

Use the Pythagorean Identity: cos²A + sin²B = 1

Use Unit Circle to evaluate: cos 45° = sin 45° = \frac{\sqrt2}{2}

<u>Proof LHS → RHS</u>

Given:                       cot\ (22\frac{1}{2})^o-tan\ (22\frac{1}{2})^o

Rewrite Fraction:     cot\ (\frac{45}{2})^o-tan\ (\frac{45}{2})^o

Half-Angle Identity:   \dfrac{sin(45)^o}{1-cos(45)^o}-\dfrac{sin(45)^o}{1+cos(45)^o}

Substitute:                  \dfrac{\frac{\sqrt2}{2}}{1-\frac{\sqrt2}{2}}-\dfrac{\frac{\sqrt2}{2}}{1+\frac{\sqrt2}{2}}

Simplify:                      \dfrac{\frac{\sqrt2}{2}}{\frac{2-\sqrt2}{2}}-\dfrac{\frac{\sqrt2}{2}}{\frac{2+\sqrt2}{2}}

                               =\dfrac{\sqrt2}{2-\sqrt2}-\dfrac{\sqrt2}{2+\sqrt2}

                               =\dfrac{\sqrt2}{2-\sqrt2}\bigg(\dfrac{2+\sqrt2}{2+\sqrt2}\bigg)-\dfrac{\sqrt2}{2+\sqrt2}\bigg(\dfrac{2-\sqrt2}{2-\sqrt2}\bigg)

                               =\dfrac{2\sqrt2+2}{4-2}-\dfrac{2\sqrt2-2}{4-2}

                               =\dfrac{4}{2}

                               = 2

LHS = RHS:  2 = 2  \checkmark

7 0
4 years ago
The sum of 2 numbers is 250. One of them is greater than 150. Which of these is definitely true about the other number?
9966 [12]
The correct answer is B-It has to be less than 100.
8 0
4 years ago
Read 2 more answers
What is the measure of arc ADB? What is the length of arc ADB? What is the area of the shaded region?
FrozenT [24]
What is the measure of arc ADB?
 The measure of the arc for this case is given by the following angle:
 theta = 360-90
 theta = 270 degrees

 What is the length of arc ADB? 

 The arc length is given by:
 s = R * theta
 Substituting values:
 s = 15 * (270 * (pi / 180))
 s = 70.69 m

 What is the area of the shaded region?

 The area of the shaded region is:
 A = (s' / s) * (pi) * (r ^ 2)
 Substituting values:
 A = (270/360) * (3.14) * (15 ^ 2)
 A = 529,875 m ^ 2
8 0
4 years ago
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