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3 years ago

Put 97.69 in word form

Mathematics

2 answers:

IceJOKER [234]3 years ago

4 0

Ninety seven and sixty nine hundredths

Pavlova-9 [17]3 years ago

3 0

97.69 in word form would be ninety seven sixty-nine thousandths

Hope this helps

Cupkake~

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10 3/9- 10 2/5 Im to lazy to do it please help me out.

coldgirl [10]

Answer:

$\boxed{ \ - \frac{3}{45} }$

Step-by-step explanation:

10 3/9 - 10 2/5

we need to convert mixed fractions to improper fractions

$10 \frac{3}{9} = \frac{10 \times 9 + 3}{9} = \frac{93}{9}$

$10 \frac{2}{5} = \frac{10 \times 5 + 2}{5} = \frac{52}{5}$

Now, we have 93/9 - 52/5

We need to equate the denominators, before subtracting them.

$\frac{93}{9} - \frac{52}{5} = \frac{93 \times 5}{45} - \frac{52 \times 9}{45}$

$\frac{465}{45} - \frac{468}{45}$

$\frac{ - 3}{45}$

$\boxed{ - \frac{3}{45} }$

The result of 10 3/9- 10 2/5 is - 3/45

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2 years ago

In sunlight, a vertical stick has a height of 5 ft and casts a shadow 3 ft long at the same time that a nearby tree casts a shad

leva [86]

The tree is 25 feet tall. Given the height of the stick and the shadow it cast, the angle formed by the sun and the stick's height can be obtained by taking the Inverse Tangent of 3/5. This is equal to 30.93. This angle is equal to the angle formed by the sun and the tree's height. Using the tangent formula, Tan (30.93)=tree's shadow (15 ft)/ height of the tree, giving the answer 25 feet.

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2 years ago

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The base and the altitude of a triangle

marishachu [46]

Answer:

base=6

Step-by-step explanation:

$\frac{base}{altitude}=\frac{1}{2}~=>2*base=altitude\\\\area=\frac{1}{2}base*altutude=\frac{1}{2}base*(2base)=base^2=36~=>base=6\\\\$

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3 years ago

1. The national mean (μ) IQ score from an IQ test is 100 with a standard deviation (s) of 15. The dean of a college wants to kno

Nat2105 [25]

Answer:

We conclude that the mean IQ of her students is different from the national average.

Step-by-step explanation:

We are given that the national mean (μ) IQ score from an IQ test is 100 with a standard deviation (s) of 15.

The dean of a college want to test whether the mean IQ of her students is different from the national average. For this, she administers IQ tests to her 144 students and calculates a mean score of 113

Let, Null Hypothesis, $H_0$ : $\mu$ = 100 {means that the mean IQ of her students is same as of national average}

Alternate Hypothesis, $H_1$ : $\mu\neq$ 100 {means that the mean IQ of her students is different from the national average}

(a) The test statistics that will be used here is One sample z-test statistics;

T.S. = $\frac{Xbar-\mu}{\frac{s}{\sqrt{n} } }$ ~ N(0,1)

where, Xbar = sample mean score = 113

s = population standard deviation = 15

n = sample of students = 144

So, test statistics = $\frac{113-100}{\frac{15}{\sqrt{144} } }$

= 10.4

Now, at 0.05 significance level, the z table gives critical value of 1.96. Since our test statistics is more than the critical value of z which means our test statistics will fall in the rejection region and we have sufficient evidence to reject our null hypothesis.

Therefore, we conclude that the mean IQ of her students is different from the national average.

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3 years ago

Nina and Luca were told to draw a net for the three-dimensional figure shown below. Which statement about the students' nets is

NISA [10]

Answer:

it was a three-dimensional figure

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2 years ago

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