Question

The following steps are used to rewrite the polynomial expression (x+4y+z)(x-7y)

Answer 1

(x+4y+z)(x-7y)=$x^{2} +4xy+xz-7xy-28y-7yz$
                       = $x^{2} -3xy+xz-7yz$

Answer 2

Answer:

The product $\left(x+4y+z\right)\left(x-7y\right)=x^2-3xy-28y^2+xz-7yz$

Step-by-step explanation:

Given expression (x+4y+z) and (x-7y)

We have to find the product of given expression that is $\left(x+4y+z\right)\left(x-7y\right)$

Consider $\left(x+4y+z\right)\left(x-7y\right)$

First multiply each term of first bracket with each term of second bracket, we have,

$=xx+x\left(-7y\right)+4yx+4y\left(-7y\right)+zx+z\left(-7y\right)$

Apply plus- minus rule, $-(-a)=a$ , we have,

$=xx-7xy+4xy-4\cdot \:7yy+xz-7yz$

Like terms are terms with same variable having same power.

Adding like terms , we have,

$=xx-3xy-4\cdot \:7yy+xz-7yz$

Simplify, we have,

$=x^2-3xy-28y^2+xz-7yz$

Thus, the product $\left(x+4y+z\right)\left(x-7y\right)=x^2-3xy-28y^2+xz-7yz$