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Ira Lisetskai [31]
4 years ago
11

On a brushed style generator, the increase in AC voltage from the ________ is fed to the automatic voltage regulator, converted

to DC voltage and fed into the rotor.
Physics
1 answer:
stealth61 [152]4 years ago
8 0

Answer:

On a brushed style generator, the increase in AC voltage from the slip rings is fed to the automatic voltage regulator, converted to DC voltage and fed into the rotor.

Explanation:

In an AC electrical generator, in order to maintain a fixed output, the output voltage  is taken from the slip rings to the brushes (some generators don't have brushes) and converted to DC voltage (since it is an AC generator) and fed back to the rotor.

The rotor winding rotate inside a stationary magnetic field known as stater which induces electrical current in the winding. These winding are connected to slip rings which transfers the current to the outside circuit.

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Suppose I create a two-slit interference pattern using light with some wavelength lambda and slits with some separation D. If I
Vlad [161]

Answer:

The pattern would spread out.

Explanation:

The fringe  width is given by the relation

fringe width = λ L / D where λ is wavelength of light used, L is distance of wall from the source of light and D is slit separation.

If we increase λ , fringe width will increase and therefore pattern will spread out .

7 0
4 years ago
distant galaxy emits light that has a wavelength of 434.1 nm. On earth, the wavelength of this light is measured to be 438.6 nm.
a_sh-v [17]

Answer:

The speed of the galaxy relative to the Earth is 3.09\times 10^6\ m/s.

Explanation:

We have,

(a) Wavelength emitted by light at distant galaxy is 434.1 nm. On earth, the wavelength of this light is measured to be 438.6 nm. It can be seen that the wavelength of light reduces as it reaches Earth. It is called Red shift. As per Doppler's effect, we can say that the galaxy is receding from the Earth.

(b) Let v is the speed of the galaxy relative to the Earth. It can be given by :

v=c(\dfrac{\lambda'}{\lambda}-1)\\\\v=3\times 10^8\times (\dfrac{438.6 }{434.1 }-1)\\\\v=3\times 10^8\times (\dfrac{438.6}{434.1}-1)\\\\v=0.0103\cdot3\cdot10^{8}\\\\v=3.09\times 10^6\ m/s

So, the speed of the galaxy relative to the Earth is 3.09\times 10^6\ m/s.

4 0
3 years ago
Which one of the following does not accurately describe the universal gravitational law? A. Gravitational force is proportional
Verizon [17]
Remark
All the statements are correct except for B

B is wrong because the Force is inversely proportional to the square of the distance.

D is correct. That's what Newton saw when he watched the apple fall. The apple did all the moving.

A is correct. The formula is 
F = G*m1*m2/r^2 
If r is held constant the formula becomes
F = k * m1 * m2 where k = G/r^2

C is true as well, but it sure decreases in strength because of the distance and the smallness of G.


7 0
3 years ago
Read 2 more answers
The mean free path of a helium atom in helium gas at standard temperature and pressure is 0.2 um.What is the radius of the heliu
ivolga24 [154]

Answer: 0.10233nm

Explanation:

The mean free path \lambda   of an atom is given by the following formula:

\lambda=\frac{RT}{\sqrt{2} \pi d^{2}N_{A}P}    (1)

Where:

\lambda=0.2\mu m=0.2(10)^{-6}m

R=8.3145J/mol.K is the Universal gas constant

T=0\°C=273.115K is the absolute standard temperature

d is the diameter of the helium atom

N_{A}=6.0221(10)^{23}/mol is the Avogadro's number

P=1atm=101.3kPa=101.3(10)^{3}Pa=101.3(10)^{3}J/m^{3} absolute standard pressure

Knowing this, let's find d from (1), in order to find the radius r of the helium atom:

d=\sqrt{\frac{RT}{\sqrt{2}\pi\lambda N_{A}P}}    (2)

d=\sqrt{\frac{(8.3145J/mol.K)(273.115K)}{\sqrt{2}\pi(0.2(10)^{-6}m)(6.0221(10)^{23}/mol)(101.3(10)^{3}J/m^{3})}}    (3)

d=2.0467(10)^{-10}m    (4)

If the radius is half the diameter:

r=\frac{d}{2}  (5)

Then:

r=\frac{2.0467(10)^{-10}m}{2}  (6)

r=1.0233(10)^{-10}m  (7)

However, we were asked to find this radius in nanometers. Knowing 1nm=(10)^{-9}m:

r=1.0233(10)^{-10}m.\frac{1nm}{(10)^{-9}m}=0.10233nm  (8)

Finally:

r=0.10233nm This is the radius of the helium atom in nanometers.

5 0
3 years ago
one of the lady spartans was falling to the ground after dunking the winning basket. At the end of her fall, she was falling 4 m
Tresset [83]

Answer:

15 is the correct answer I.t.

8 0
3 years ago
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