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EastWind [94]
4 years ago
5

What is the magnitude of the kinetic frictional force

Physics
1 answer:
Sophie [7]4 years ago
3 0

Answer:

Magnitude of kinetic force is the product of the normal force and the coefficient of kinetic friction.

Explanation:

The kinetic frictional force is the force which is experienced in the moving surfaces of bodies.The magnitude of the force is affected by the coefficient of kinetic friction between the material of two bodies in contact. Mathematically, it is expressed as;

Fk=μk*η

where;

  • Fk=force of kinetic friction
  • μk=coefficient of kinetic friction
  • η=normal force
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If the mass of an object is 10 Kg and it experiences a Net force of 60 Newtons. What is the acceleration?
Solnce55 [7]

Answer:

6 m/s^2

Explanation:

F = ma

60N = (10 kg)a

a = 6m/s^2

3 0
3 years ago
How much net force is needed to accelerate a 15 kg mass at 2.8 m/s^2
Lera25 [3.4K]
Refer to the 2th Law of Newton

F = m. a

F = 15 x 2.8 = 42 N
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What is someones target heart rate at 70% at age 17​
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Answer: normal

Explanation:

6 0
3 years ago
Label these as balanced or unbalanced:
kvasek [131]

Answer:

  1. A book lying on a table  - Balanced force
  2. An airplane cruising in level flight  - Balanced
  3. A rock falling from a cliff  - Unbalanced force
  4. A bridge collapsing in an earthquake  -  Unbalanced force
  5. A man sitting on a park bench  - Balanced force
  6. A space shuttle taking off  - Unbalanced force
  7. A car maintaining a constant speed on a straight road  - Balanced force
  8. An airplane landing - Unbalanced force

Explanation:

Usually, one or more forces act on a body at an instant of time. When these forces acting on a body and bring the body in the equilibrium position, the force is said to be balanced. The unbalanced force changes the equilibrium state of the body.

As in the case of an airplane cruising in a level flight, the weight of the plane will be equal to the lift force and the thrust is equal to the drag. So the plane is experiencing a balanced force.

4 0
3 years ago
Read 2 more answers
A dockworker loading crates on a ship finds that a 21-kg crate, initially at rest on a horizontal surface, requires a 73-N horiz
Nataliya [291]

1) Static friction coefficient: 0.355

The crate is initially at rest. The crate remains at rest until the horizontal pushing force is less than the maximum static frictional force.

The maximum static frictional force is given by

F_s = \mu_s mg

where

\mu_s is the static coefficient of friction

m = 21 kg is the mass of the crate

g = 9.8 m/s^2 is the acceleration due to gravity

The horizontal force required to set the crate in motion is 73 N: this means that this is the value of the maximum static frictional force. So we have

F_s=73 N

Using this information into the previous equation, we can find the coefficient of static friction:

\mu_s = \frac{F}{mg}=\frac{73 N}{(21 kg)(9.8 m/s^2)}=0.355

2) Kinetic friction coefficient: 0.267

Now the crate is in motion: this means that the kinetic friction is acting on the crate, and its magnitude is

F_k = \mu_k mg (1)

where

\mu_k is the coefficient of kinetic friction

There is a horizontal force of

F = 55 N

pushing the crate. Moreover, the speed of the crate is constant: this means that the acceleration is zero, a = 0.

So we can write Newton's second law as

F-F_k = ma = 0

And by substituting (1), we can find the value of the coefficient of kinetic friction:

F-\mu_k mg = 0\\\mu_k = \frac{F}{mg}=\frac{55 N}{(21 kg)(9.8 m/s^2)}=0.267

5 0
4 years ago
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