Question

8) 8 resistor is connected in **parallel** with a 6 resistor. This

Answer 1

Answer:

The equivalent resistance of the combination is 3.42 ohms.  

Explanation:

We have,

8 ohms resistor is connected in parallel with a 6 ohms resistor. It is required to find the equivalent resistance of this combination.

For a parallel combination, the equivalent resistance is given by :

$\dfrac{1}{R_{eq}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}$

Plugging the values of R₁ and R₂, we get :

$\dfrac{1}{R_{eq}}=\dfrac{1}{8}+\dfrac{1}{6}\\\\R_{eq}=3.42\ \Omega$

So, the equivalent resistance of the combination is 3.42 ohms.