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2 years ago

Solve for x. x/3≤−6 x≤−18 x≤−2 x≥−2 x≥−18

Mathematics

1 answer:

ella [17]2 years ago

5 0

X is less than or equal to -18

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Caleb bought groceries and paid

lutik1710 [3]

Answer:

Price of Caleb's groceries before tax= $6.4

Step-by-step explanation:

Let price of groceries before tax be = $ $x$

Sales tax % = 2.5%

Sales tax applied = $2.5\% \ of\ x = \frac{25}{100}\times x = \frac{25}{100} x$

Actual sales tax paid = $1.60

∴ $\frac{25}{100}x=1.60$

Multiplying both sides by 100.

$100\times \frac{25}{100}x=1.60\times 100$

$25x=160$

Dividing both sides by 25.

$\frac{25x}{25}=\frac{160}{25}$

$x=6.4$

∴ Price of groceries before tax= $6.4

8 0

2 years ago

Read 2 more answers

Help with these please and highly appreciate the help !!!!!!!

k0ka [10]

Which one will we start with? I'll explain 21. multiply it out and the clean it up. you should end up with 140=A if I'm correct.

7 0

3 years ago

attashe74 [19]

Answer:

y= 3/4x

Step-by-step explanation:

Points on the graph

(0, 0), (4, 3)

the equation based on the difference in points:

y= 3/4x

6 0

2 years ago

Read 2 more answers

Shortly after their arrival, Europeans began introducing pigs to the Americas as a source of food. Some escaped, and others were

natka813 [3]

Answer: About 800 thousand

The more accurate value is 807,528 but this is also an approximation.

=======================================================

Work Shown:

$t = \text{number of years since the year 2000}$

$P_0 = \text{population (in millions) in the year 2000}$

$P = P_0(1.2)^t\\\\5 = P_0(1.2)^{10}\\\\5 \approx P_0*6.1917364224\\\\P_0 \approx \frac{5}{6.1917364224}\\\\P_0 \approx 0.80752791444922\\\\P_0 \approx 0.807528\\\\$

That's the rough population of wild pigs (in millions) for the year 2000.

Multiply by $10^6$ to get it in terms of units instead.

$0.807528\times10^6 = 807,528$

There were roughly 800 thousand wild pigs in the year 2000.

7 0

1 year ago

If a tightrope walker falls, he will land on a safety net. His height h in feet after a fall can be modeled by h(t) = 60 - 16t2,

hjlf

As we know that
h = 60 - 16t^2 
t = sqrt((60 - h)/16) 
= sqrt((60 - 11)/16) 
= 1.75
hope it helps

7 0

2 years ago