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3 years ago

Does anyone know about this one? I appreciate you guys helping me((:

Mathematics

2 answers:

LenaWriter [7]3 years ago

6 0

For your question the answer is B.

 Hope this helps:)

ratelena [41]3 years ago

6 0

your answer is b hope i helpedd

You might be interested in

There are two formulae you can use to calculate the number of apple trees and the number of conifer

Leno4ka [110]

9514 1404 393

Answer:

n = 8

Step-by-step explanation:

"By inspection" is an appropriate method.

We are asked to compare the expressions

n·n

8·n

and find the value(s) of n that makes them equal. By inspection, we see that n=8 will make these expressions equal. We also know that both expressions will be zero when n=0.

More formally, we could write ...

n^2 = 8n . . . . the two formulas give the same value

n^2 -8n = 0 . . . . rearrange to standard form

n(n -8) = 0 . . . . . factor

Using the zero product rule, we know the solutions will be the values of n that make the factors zero. Those values are ...

n = 0 . . . . . makes the factor n = 0

n = 8 . . . . . makes the factor (n-8) = 0

Generally, we're not interested in "trivial" solutions (n=0), so the only value of n that is of interest is n = 8.

A lot of times, I find a graphing calculator to be a quick and easy way to find function argument values that make expressions equal.

5 0

3 years ago

Can someone please answer this?

telo118 [61]

Yes i can answer this

8 0

3 years ago

An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t

USPshnik [31]

The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

$\displaystyle\int_a^bf(x)\,\mathrm dx$

Split up the interval $[a,b]$ into $n$ equal subintervals,

$[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]$

where $a=x_0$ and $b=x_n$ . Each subinterval has measure (width) $\dfrac{a-b}n$ .

Now denote the left- and right-endpoint approximations by $L$ and $R$ , respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are $\{x_0,x_1,\cdots,x_{n-1}\}$ . Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, $\{x_1,x_2,\cdots,x_n\}$ .

So, you have

$L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)$
$R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)$

Now let $T$ denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

$T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)$

Factoring out $\dfrac12$ and regrouping the terms, you have

$T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)$

which is equivalent to

$T=\dfrac12\left(L+R)$

and is the average of $L$ and $R$ .

So the trapezoidal approximation for your problem should be $\dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2$

4 0

3 years ago

A cylinder has a radius of 4x + 2 and a height of 5x + 4. Which polynomial in standard form best describes the total volume of t

forsale [732]

V = π r² h
V= π (4x+2)² (5x+4)
V = π (4x+2)(4x+2)(5x+4)
V = π (16x²+16x+4)(5x+4)
V= π(80x³+144x²+84x+16)
V= 251.33x³ +452.39x²+263.89x+50.27

4 0

3 years ago

Does the equation y=14x represennt a proportinal relationship?

Sonbull [250]

Y=14x
Compare with general form:
y=kx
Where k is the constant of proportionality.
Here k=14
So 1 unit increase in x will bring 14 times increase in y.
There is a direct relation between x and y.

Answer: Yes

5 0

3 years ago