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MakcuM [25]
3 years ago
10

A machine is supplied Energy at a rate of 4000 W and does useful work at a rate of 3760 W. What is the efficiency of the machine

?
Physics
2 answers:
ICE Princess25 [194]3 years ago
6 0
The efficiency of a machine is the ratio between the output power and the power in input:
\epsilon =  \frac{P_{out}}{P_{in}}
in our problem, the output power is 3760 W while the input power is 4000 W, so the efficiency is
\epsilon =  \frac{3760 W}{4000 W} =0.94
So the efficiency of the machine is 94%.
Alex17521 [72]3 years ago
5 0

Answer:

94%

Explanation:

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If =12a andthe distance from each wire to point p is 0.12m, then what is the magnitude of the magnetic force per unit length on
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The magnitude of the magnetic force per unit length on the top wire is

2×10⁻⁵  N/m

<h3>How can we calculate the magnitude of the magnetic force per unit length on the top wire ?</h3>

To calculate the magnitude of the magnetic force per unit length on the top wire, we are using the formula

F= \frac{\mu_0 I_f}{2\pi d}

Here we are given,

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Now we put the known values in the above equation, we get

F= \frac{\mu_0 I_f}{2\pi d}

Or, F = \frac{4\pi \times 10^{-7}\times  12}{2\pi \times 0.12}

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7 0
2 years ago
A friend of yours is loudly singing a single note at 412 Hz while racing toward you at 25.8 m/s on a day when the speed of sound
xeze [42]

Answer:

5541Hz

Explanation:

If the frequency of a wave is directly proportional to the velocity we have;

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Since f = kV

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412/25.8=f2/347

Cross multiplying

25.8f2 = 412×347

F2 = 412×347/25.8

F2 = 5541Hz

The frequency heard will be 5541Hz

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