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3 years ago

HEEEEELLLLLLLLLLLLLLLLPPPPPPPPPPPPPPP i need to get unstuck

Physics

2 answers:

pochemuha3 years ago

8 0

Geyshbdgsggefsgahevayagvdvdgavd

guapka [62]3 years ago

4 0

Answer:

say lesssssss

Explanation:

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If each of the three rotor helicopter blades is 3.50 m long and has a mass of 120 kg , calculate the moment of inertia of the th

devlian [24]

Answer:

1470kgm²

Explanation:

The formula for expressing the moment of inertial is expressed as;

I = 1/3mr²

m is the mass of the body

r is the radius

Since there are three rotor blades, the moment of inertia will be;

I = 3(1/3mr²)

I = mr²

Given

m = 120kg

r = 3.50m

Required

Moment of inertia

Substitute the given values and get I

I = 120(3.50)²

I = 120(12.25)

I = 1470kgm²

Hence the moment of inertial of the three rotor blades about the axis of rotation is 1470kgm²

7 0

3 years ago

An oil slick on water is 120 nm thick and illuminated by white light incident perpendicular to its surface. What color does the

gregori [183]

Answer:

$\lambda = 672 nm$

so this is nearly red colour light

Explanation:

As we know that the interference of light from reflected light then the path difference is given as

$\Delta x = 2\mu t + \frac{\lambda}{2}$

now we know that for constructive interference of light the path difference is given as

$\Delta x = n\lambda$

so we will have

$2\mu t + \frac{\lambda}{2} = N\lambda$

so we will have

$4\mu t = \lambda$

$\lambda = 2(1.40)(120nm)$

$\lambda = 672 nm$

so this is nearly red colour light

8 0

3 years ago

A mango is dropped and fall freely from rest. What are its position and velocity after 1.0secs,2.0secs,and 3.0secs

irakobra [83]

Answer:

sxsdfsd

Explanation:

4 0

3 years ago

You observe a hockey puck of mass 0.12 kg, traveling across the ice at speed 18.3 m/sec. The interaction of the puck and the ice

Galina-37 [17]

The stopping distance is 143.1 m

Explanation:

First of all, we have to find the acceleration of the hockey puck. This can be done by using Newton's second law of motion:

$\sum F =ma$

where

$\sum F = F_f = -0.14 N$ is the net force acting on the puck (the force of friction, negative because it acts in a direction opposite to the direction of motion)

m = 0.12 kg is the mass of the puck

a is the acceleration

Solving for a,

$a=\frac{\sum F}{m}=\frac{-0.14}{0.12}=-1.17 m/s^2$

The motion of the puck is a uniformly accelerated motion, therefore we can use the following suvat equation:

$v^2-u^2=2as$

where:

v = 0 is the final velocity (the puck comes to a stop)

u = 18.3 m/s is the initial velocity

$a=-1.17 m/s^2$ is the acceleration

s is the stopping distance

And solving for s, we find

$s=\frac{v^2-u^2}{2a}=\frac{0-(18.3)^2}{2(-1.17)}=143.1 m$

Learn more about accelerated motion:

brainly.com/question/9527152

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brainly.com/question/2506873

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#LearnwithBrainly

6 0

3 years ago

The higher u hold something above the ground? A. The less potential B. The more kinetic energy it has C. The more potential ener

fredd [130]

I think is B or C

maby is C

6 0

3 years ago

Read 2 more answers