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kykrilka [37]
3 years ago
12

Exactly one pound of bread dough is placed in a baking tin. the dough is cooked in an oven at 350 °f releasing a wonderful aroma

of freshly baked bread during the cooking process. is the mass of the baked loaf less than, greater than, or the same as the one pound of original dough? explain.
Physics
1 answer:
Sladkaya [172]3 years ago
7 0
The mass of the baked loaf will be less than the original dough. In making dough for bread, we have ingredients that are liquid such as water, melted butter, food flavoring, etc. All of this liquid ingredients mixed on the dough will definitely turn into vapor. This vapor is responsible for releasing of the aroma of the freshly baked bread.
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A vertical spring with a spring constant of 310 N/m is mounted on the floor. From directly above the spring, which is unstrained
EleoNora [17]

Answer:

7.3cm above the compressed spring.

Explanation:

We can use the conservation energy theorem to solve this problem:

U_{1}+K_1=U_e+U_2+K_2\\m*g*h+0=\frac{1}{2}k*x^2+0+0\\\\h=\frac{k*x^2}{2*m*g}\\\\h=\frac{310N/m*(3.6*10^{-2})^2}{2*0.28kg*9.8m/s^2}\\\\h=0.073m

The block was dropped 7.3cm above the compressed spring.

8 0
3 years ago
Just a question anybody playing minècraft here?
yan [13]

Answer:

yes/nope

Explanation:

............... :)

5 0
2 years ago
Read 2 more answers
The rate at which work is done is known as which of the following?
sveta [45]

Answer:

A , power

Explanation:

Hope this is useful. Have a lovely rest of your day! God bless you.

3 0
3 years ago
A 0.560 kg snowball is fired from a cliff 14.2 m high with an initial velocity of 13.3 m/s, directed 26.0° above the horizontal.
enot [183]

Answer:

a) v = 21.34 m/s

b) v = 21.34 m/s

c) v = 21.34 m/s

Explanation:

Mass of the snowball, m = 0.560 kg

Height of the cliff, h = 14.2 m

Initial velocity of the ball, u = 13.3 m/s

θ = 26°

The speed of the slow ball as it reaches the ground, v = ?

The initial Kinetic energy of the snow ball, KE_{0}  = 0.5 mu^{2}

Potential energy of the snow ball at the given height, PE = mgh

Final Kinetic energy of the ball as it reaches the ground, KE_{f} = 0.5mv^{2}

a) Using the principle of energy conservation,

KE_{0} + PE = KE_{f} \\0.5mu^{2} + mgh = 0.5mv^{2}\\v^{2} =2( 0.5u^{2} + gh)\\v^{2} =u^{2} + 2gh\\v = \sqrt{u^{2} + 2gh} \\v = \sqrt{13.3^{2} + 2*9.8*14.2}\\v = 21.34 m/s

b) The speed remains v = 21.34 m/s since it is not a function of the angle of launch

c)The principle of energy conservation used cancels out the mass of the object, therefore the speed is not dependent on mass

v = 21. 34 m/s

7 0
4 years ago
Match the letter and term.
rosijanka [135]

Answer:

1. Nitrogen

2. Oxygen

3. Carbon dioxide

4. Water vapor

5. Ozone

Explanation:

The atmosphere composes of 78% nitrogen which occupies the largest percentage followed by oxygen which takes up 21%, Argon takes up 1% then other components such as water vapor occupy between 0-7% and ozone takes 0.0-0.01. Moreover, 0.01-0.1 is occupied by carbon dioxide. Therefore, the answers for 1-5 are as follows.

1. Nitrogen

2. Oxygen

3. Carbon dioxide

4. Water vapor

5. Ozone

4 0
3 years ago
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