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a_sh-v [17]
3 years ago
9

The sum of the reciprocals of two consecutive integers is -9/20. Find the two integers

Mathematics
1 answer:
mr_godi [17]3 years ago
5 0
Suppose the first integer is x, the second one is then x+1
reciprocals are 1/x and 1/(x+1)
1/x +1/(x+1)=-9/20
make the denominators the same:
1(x+1)/x(x+1) + 1x/x(x+1)=-9/20
simplify the demonstrator and add up the numerators: (2x+1)/(x^2+x)=-9/20
20(2x+1)=-9(x^2+x)
40x+20=-9x^2-9x
9x^2 +49x+20=0
factor: (1+5)(9x+4)=0
x=-5 or x=-4/9 (this one doesn't work because it is not an integer)
so the first integer is -5, the second integer is -4

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Kruka [31]
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How do you leave an answer in terms of pi?
Archy [21]

In terms of pi means to include pi in your answer. In other words, don't use 3.14 or 22/7 for pi.

8 0
3 years ago
There are three consecutive integers such that the sum of the two smallest integers is 17 less than three times the largest.What
abruzzese [7]
ANSWER:

Let the smallest integer = x

x + x + 1 = 3 ( x + 2 ) - 17

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2x - 3x = 6 - 17 - 1

- x = - 12

x = 12

FINAL ANSWER:

Therefore, the smallest integer is 12.

Please mark as brainliest if you found this helpful! :)
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6 0
3 years ago
Lynn plotted point G, 3 units to the left and 2 units above point F. Where did lynn plot point G?
kvasek [131]

Answer:

G = (2,6)

Step-by-step explanation:

See Attachment for Complete Question

From the attachment, we can see that F is plotted at

F = (5,4)

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And on the y axis, G is 2 units above

So, the coordinates of G is calculated as:

G = (5-3,4+2)

G = (2,6)

Hence:

<em>G is plotted at (2,6)</em>

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