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ivanzaharov [21]
3 years ago
12

A driver in a car traveling at a speed of 21.8 m/s sees a cat 101 m away on the road. How long will it take for the car to accel

erate uniformly to a stop in exactly 99 m?
Mathematics
1 answer:
Bogdan [553]3 years ago
5 0

Answer:

t = 9.08 sec

Explanation :

This requires the use of the kinematic equations.

u = initial velocity = 21.8 m/s

v = final velocity = 0

t = time = what we're trying to find.

So we use the equation that relates d, u, v and t. This is

d = distance = 99m

d = \frac{t*(u+v)}{2}

and since v = 0 this reduces to d = \frac{tu}{2}

which rearranges to t = \frac{2d}{u}

t = \frac{2*99}{21.8} =9.08 seconds

t = 9.08 sec



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Answer:

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Step-by-step explanation:

The given relation between length and width can be used to write an expression for area. The equation setting that equal to the given area can be solved to find the shed dimensions.

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<h3>Given relation</h3>

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Completing the square gives ...

  2x² +3x +1.125 = 21.125 . . . . . . add 2(9/16) to both sides

  2(x +0.75)² = 21.125 . . . . . . . write as a square

  x +0.75 = √10.5625 . . . . . divide by 2, take the square root

  x = -0.75 +3.25 = 2.50 . . . . . subtract 0.75, keep the positive solution

The width of the shed is 2.5 feet; the length is 2(2.5)+3 = 8 feet.

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