2/7 is the probability that the first satellite sends a weak signal. That leaves 6, one of which sends a weak signal. So the probability that the second also sends a weak signal is 1/6. Combine these and we get 2/7×1/6=1/21.
There is no graph I’m sorry I can’t help
Answer:
S = 3.500t
11 weeks, because in 11 weeks he will have saved up 38.500, + the 5 he has saved equals 43.500.
Step-by-step explanation:
Let X be the random variable denoting the number of successful throws.
Here X~ Binomial Distribution with n = 5 and p = 0.80.
the probability of her missing 3 (or more) free throws out of 5
= P ( X ≤ 2)
= P (X= 0) + P(X= 1) + P(X= 2)
=0.00032 + 0.0064 + 0.0512
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= 0.05792
I hope my answer has come to your help. God bless and have a nice day ahead!
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