3 years ago

What are the dimensions of the drawing?

Mathematics

1 answer:

chubhunter [2.5K]3 years ago

5 0

I don't know this but good luck

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Given: m∠1 = 140°, find m∠6.

zavuch27 [327]

<h2>Answer:</h2>

Let m<6 be X

140° + X = 180°

X = 180° - 140°

X =40°

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3 years ago

If ln(a)=2, ln(b)=3, and ln(c)=5, evaluate the following: ln(a^-4/b^1 c^1)

Mila [183]

Ln ( a^(-4) / b^1 c^1 ) =
= ln a ^(-4) - ( ln b + ln c ) =
= - 4 ln a - ln b - ln c =
= - 4 * 2 - 3 - 5 =
= - 8 - 3 - 5 = - 16

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3 years ago

What function corresponds to the ordered pairs shown in the table?

Anettt [7]

well, we know it's a line, and to get the equation of any line all we need is two points, let's pick two from the table hmmmm say let's use (-3 , -7) and (3 , 11)

$(\stackrel{x_1}{-3}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{11}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{11}-\stackrel{y1}{(-7)}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{(-3)}}}\implies \cfrac{11+7}{3+3}\implies \cfrac{18}{6}\implies 3$

$\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-7)}=\stackrel{m}{3}(x-\stackrel{x_1}{(-3)}) \\\\\\ y+7=3(x+3)\implies y+7=3x+9\implies y = 3x+2$