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2 years ago

The number of peaches, p, is three less than half the number of grapes, g.

Mathematics

1 answer:

Hoochie [10]2 years ago

7 0

the answer to this question would be 3g-2 because you need to use functions and function notation

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1. f (x) = 5x + 10. If x = 10, then what is the value of f(x)?

UkoKoshka [18]

Answer:

B: 60

Step-by-step explanation:

f(x)= 5x+10, if x=10

f(10)=5(10)+10

5(10)+10=60

f(10)=60

3 0

3 years ago

What is the selling price of a $610 couch with a 25% markup?

defon

Answer:

762.5

Step-by-step explanation:

25% of 610 is 152.5 and 610 + 152.5 is 762.5

Hope this helped also can i get brainliest?

8 0

3 years ago

In an experiment, college students were given either four quarters or a $1 bill and they could either keep the money or spend it

gavmur [86]

Answer:

a) $P(A|B) = \frac{15/83}{44/83} =\frac{15}{44}=0.341$

b) $P(B|A) = \frac{29/83}{44/83} =\frac{29}{44}=0.659$

c) A. A student given a $1 bill is more likely to have kept the money.

Because the probability 0.659 is atmoslt two times greater than 0.341

Step-by-step explanation:

Assuming the following table:

Purchased Gum Kept the Money Total

Students Given 4 Quarters 25 14 39

Students Given $1 Bill 15 29 44

Total 40 43 83

a. find the probability of randomly selecting a student who spent the money, given that the student was given a $1 bill.

For this case let's define the following events

B= "student was given $1 Bill"

A="The student spent the money"

For this case we want this conditional probability:

$P(A|B) =\frac{P(A and B)}{P(B)}$

We have that $P(A)= \frac{40}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{15}{83}$

And if we replace we got:

$P(A|B) = \frac{15/83}{44/83} =\frac{15}{44}=0.341$

b. find the probability of randomly selecting a student who kept the money, given that the student was given a $1 bill.

For this case let's define the following events

B= "student was given $1 Bill"

A="The student kept the money"

For this case we want this conditional probability:

$P(A|B) =\frac{P(A and B)}{P(B)}$

We have that $P(A)= \frac{43}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{29}{83}$

And if we replace we got:

$P(B|A) = \frac{29/83}{44/83} =\frac{29}{44}=0.659$

c. what do the preceding results suggest?

For this case the best solution is:

A. A student given a $1 bill is more likely to have kept the money.

Because the probability 0.659 is atmoslt two times greater than 0.341

3 0

3 years ago

Cube-shaped boxes will be loaded into the cargo hold of a truck. The cargo hold of the truck is in the shape of a rectangular pr

Mrrafil [7]

Solve each problem. Volume of a Box A piece of sheet metal is 2.5 times as long as it is wide. It is to be made into a box with an open top by cutting 3 -inch squares from each corner and folding up the sides, as shown at the top of the next page. Let x
represent the width of the original piece of sheet metal. (a) Represent the length of the original piece of sheet metal in terms of x.
(b) What are the restrictions on x?
(c) Determine a function V
that represents the volume of the box in terms of x
(d) For what values of x
(that is, original widths) will the volume of the box be between 600 and 800 cubic inches? Determine the answer graphically, and give values to the nearest tenth of an inch

3 0

2 years ago

Which points are on the graph of g(x) = (1/5)^x

11111nata11111 [884]

Answer:

A) The point( -1 , 5) is satisfies the given graph $g(x) = (\frac{1}{5} )^{x}$

B) The point( 3 , 1/125) is satisfies the given graph $g(x) = (\frac{1}{5} )^{x}$

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given graph

y = $g(x) = (\frac{1}{5} )^{x}$

Put the point ( -1 , 5)

Put y =5 and x =-1

$5 = (\frac{1}{5} )^{-1} = 5$

The point( -1 , 5) is satisfies the given graph

ii)

Given graph

y = $g(x) = (\frac{1}{5} )^{x}$

$\frac{1}{125} = (\frac{1}{5} )^{3} = \frac{1}{125}$

The point( 3 , 1/125) is satisfies the given graph $g(x) = (\frac{1}{5} )^{x}$

7 0

3 years ago