1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sveta [45]
3 years ago
5

|2x + 2| greater than or equal to - 14

Mathematics
1 answer:
Elenna [48]3 years ago
6 0
D there is really no solution unless u get the value of x which I do not have so it can only be simplified into this equation above I hope this is correct and helpful

You might be interested in
5. Lisa sold costume jewelry at a bazaar. The
julsineya [31]

Answer:

$4

Step-by-step explanation:

2 Bracelets + 3 rings = $26

2 rings = $12

3 rings = x

To get the cost of 1 ring you divide 12 by 2 and the answer you get is 6.

The total cost of the 3 rings is $18( $6*3)

Then you subtract the cost of both 2 bracelets and 3 rings($26) from the cost of 3 rings($18). The answer is $8. ( THIS IS THE COST OF 2 BRACELETS)

<u>1 BRACELET= $4( $8/2)</u>

8 0
3 years ago
What is the square root of -1
Zinaida [17]

Answer:

i

Step-by-step explanation:

square root of -1 is i

6 0
3 years ago
Read 2 more answers
Please solve<br>x^2+6x+5=0​
Inessa [10]

Answer:

plus the other number and the other one

8 0
2 years ago
4 is equivalent to how hundreths
zzz [600]
4 = 400/100
or 400 hundreths
6 0
3 years ago
Read 2 more answers
Evaluate the triple integral ∭EzdV where E is the solid bounded by the cylinder y2+z2=81 and the planes x=0,y=9x and z=0 in the
dem82 [27]

Answer:

I = 91.125

Step-by-step explanation:

Given that:

I = \int \int_E \int zdV where E is bounded by the cylinder y^2 + z^2 = 81 and the planes x = 0 , y = 9x and z = 0 in the first octant.

The initial activity to carry out is to determine the limits of the region

since curve z = 0 and y^2 + z^2 = 81

∴ z^2 = 81 - y^2

z = \sqrt{81 - y^2}

Thus, z lies between 0 to \sqrt{81 - y^2}

GIven curve x = 0 and y = 9x

x =\dfrac{y}{9}

As such,x lies between 0 to \dfrac{y}{9}

Given curve x = 0 , x =\dfrac{y}{9} and z = 0, y^2 + z^2 = 81

y = 0 and

y^2 = 81 \\ \\ y = \sqrt{81}  \\ \\  y = 9

∴ y lies between 0 and 9

Then I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \int^{\sqrt{81-y^2}}_{z=0} \ zdzdxdy

I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix} \dfrac{z^2}{2} \end {bmatrix}    ^ {\sqrt {{81-y^2}}}_{0} \ dxdy

I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix}  \dfrac{(\sqrt{81 -y^2})^2 }{2}-0  \end {bmatrix}     \ dxdy

I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix}  \dfrac{{81 -y^2} }{2} \end {bmatrix}     \ dxdy

I = \int^9_{y=0}  \begin {bmatrix}  \dfrac{{81x -xy^2} }{2} \end {bmatrix} ^{\dfrac{y}{9}}_{0}    \ dy

I = \int^9_{y=0}  \begin {bmatrix}  \dfrac{{81(\dfrac{y}{9}) -(\dfrac{y}{9})y^2} }{2}-0 \end {bmatrix}     \ dy

I = \int^9_{y=0}  \begin {bmatrix}  \dfrac{{81 \  y -y^3} }{18} \end {bmatrix}     \ dy

I = \dfrac{1}{18} \int^9_{y=0}  \begin {bmatrix}  {81 \  y -y^3}  \end {bmatrix}     \ dy

I = \dfrac{1}{18}  \begin {bmatrix}  {81 \ \dfrac{y^2}{2} - \dfrac{y^4}{4}}  \end {bmatrix}^9_0

I = \dfrac{1}{18}  \begin {bmatrix}  {40.5 \ (9^2) - \dfrac{9^4}{4}}  \end {bmatrix}

I = \dfrac{1}{18}  \begin {bmatrix}  3280.5 - 1640.25  \end {bmatrix}

I = \dfrac{1}{18}  \begin {bmatrix}  1640.25  \end {bmatrix}

I = 91.125

4 0
3 years ago
Other questions:
  • How many 6 ounce cups can be filled from 4 gallons of juice?
    6·2 answers
  • Using the volume of a cylinder formula. Calculate the volume of the cylinder. *
    5·1 answer
  • The speed of light in vacuum is 2.998x10^8 m/s. What is the speed in km/hr and mi/min?
    7·2 answers
  • HELP PLEASE!!!! ASAP!!! Describe, with examples of your own, when you would use long division and synthetic division and how to
    12·1 answer
  • What is the missing statement in step 10 of the proof?
    15·1 answer
  • How do you solve for range because i’m so confused lol
    11·1 answer
  • I need help with this question
    11·2 answers
  • The graph of a function is shown below.​<br> ​ <br> ​Is the function linear?
    7·2 answers
  • A man claims to have extrasensory perception (ESP). As a test, a fair coin is flipped 23 times, and the man is asked to predict
    6·1 answer
  • CAN SOMEONE PLEASE HELP WITH MY MATH??? LOOK AT THE PHOTO PLEASEEE I NEED THIS ASAP
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!