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3 years ago

Saturated hydrocarbons with what length of carbon chain are the best lubricants?

1 answer:

3 0

For the answer to the question above, the best lubricant has around 17-35 saturated hydrocarbons. Lubricants can either be liquid (oils) or solid (grease). Oils typically have 15-20 carbon atom chains, while grease has 20-35 carbon atoms chains. This means that both lubricant types fall under the range 17-37.

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Calculate the theoretical density of iron, and then determine the number of vacancies per cm3 needed for a BCC iron crystal to h

Ann [662]

Answer:

Therefore the theoretical density of iron is 7.877 g/cm³ .

Therefore the number of vacancy per cm³ is $3.27 \times 10^{20}$

Explanation:

BCC structure contains 2 atoms per cell.

BCC : Body centered cubic.

Atomic mass of iron = 55.845 gram/mole.

Atomic mass of a chemical element is the mass of 1 mole of the chemical element.

Density: Density of a matter is the ratio of mass of the matter and volume of the matter.

Avogrdro Number is number of atoms per 1 mole.

Avogrdro Number= 6.023×10²³

Lattice parameter of iron = 2.866×10⁻⁸ cm

The theoretical density:

$\rho=\frac{\textrm{(x atom/cell)} \times \textrm{(atomic mass)}}{\textrm{avogadro's number}\times \textrm{(lattice parameter)}^3}$

$=\frac{2\times 55.845 }{(6.023\times 10^{23})\times (2.866\times 10^{-8})^3}$ g/cm³ [x= 2,Since it is BCC structure]

=7.877 g/cm³

Therefore the theoretical density of iron is 7.877 g/cm³ .

Now we have to find out the number of unit cell of iron crystal having density 7.874 g/cm³.

$\rho=\frac{\textrm{(x atom/cell)} \times \textrm{(atomic mass)}}{\textrm{avogadro's number}\times \textrm{(lattice parameter)}^3}$

$\Rightarrow 7.874 =\frac{x\times 55.845}{6.023\times 10^{23}\times (2.866\times 10^{-8})^3}$

$\Rightarrow x= \frac{7.874\times 6.023\times 10^{23}\times (2.866\times 10^{-8})^3}{55.845}$

⇒ x =1.9923 atom/cell

Therefore the vacancy of atom per cell = (2- 1.9923)=0.0077

$Vacancy\ per\ cm^3=\frac{\textrm{Vacancy per cm} ^3 }{\textrm{( lattice parameter)} ^3}$

$=\frac{0.0077}{(2.866\times 10^-8)^3}$

$=3.27 \times 10^{20}$

Therefore the number of vacancy per cm³ is $3.27 \times 10^{20}$

5 0

3 years ago

What period is Pb in

ad-work [718]

Pb (lead) is in the 6th period

(please give brainliest if this helped you)

4 0

3 years ago

Initial temperature of metal= 100 C°

Vilka [71]

Water is 22.4

Final for both us 27.1

Explanation:

I just finished this part of the lab

3 0

3 years ago

7. A square chunk of plastic has a length of 5 cm, width of 5 cm and height of 5 cm. It has a mass of 200 g. What is its density

BaLLatris [955]

Answer:

$d=1.6\ g/cm^3$

Explanation:

Given that,

The dimension of a square chunk of plastic is 5 cm × 5 cm × 5 cm

Mass, m = 200 g

We need to find its density

Density = mass/volume

It will form a cube. It volume = side³

So,

$d=\dfrac{200\ g}{5^3\ cm^3}\\\\d=1.6\ g/cm^3$

Hence density is $1.6\ g/cm^3$

5 0

4 years ago

A student sets up a compost bin outdoors. Inside the bin microorganisms convert the student’s vegetable and paper scraps into ri

zhenek [66]

B i think thats it,.,,.,

6 0

3 years ago