(4x1000) + (2x100) + (3x1/10)
2 answers:
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Answer: (A)
Explanation: For there to be a solution at any one point, both inequalities must share a common point. This point will then satisfy both inequations, becoming a solution to both inequality.
Let's pick (A).
For there to be at least one solution, the first inequality must have a solution of
. Since the left side has clearly no points common to both graphs. Hence, no solution can exist that will satisfy both.
All of the other graphs have at least one point in common.
(B) has
(C) has
(D) has
Explanation: For there to be a solution at any one point, both inequalities must share a common point. This point will then satisfy both inequations, becoming a solution to both inequality.
Let's pick (A).
For there to be at least one solution, the first inequality must have a solution of
All of the other graphs have at least one point in common.
(B) has
(C) has
(D) has