Question

Suppose that g (x) varies inversely with x and g (x)=0.2 when x = 0.1.

Answer 1

Answer : 0.0125

Suppose that g (x) varies inversely with x and g (x)=0.2 when x = 0.1.

If x varies inversely with y then y=k/x

Where k is constant of proportionality

g (x) varies inversely with x , so $g(x) = \frac{k}{x}$

g (x)=0.2 when x = 0.1

Plug in the values and solve for k

$g(x) = \frac{k}{x}$

$0.2 = \frac{k}{0.1}$

Multiply 0.1 on both sides

0.02 = k

so $g(x) = \frac{0.02}{x}$

Now we need to find g(x) when x= 1.6

Plug in 1.6 for x  and find out g(x) in the above equation

$g(x) = \frac{0.02}{1.6}$

g(x)= 0.0125