Can you put more information into this question
Answer:
We assume, that the number 180 is 100% - because it's the output value of the task.
2. We assume, that x is the value we are looking for.
3. If 100% equals 180, so we can write it down as 100%=180.
4. We know, that x% equals 483.6 of the output value, so we can write it down as x%=483.6.
5. Now we have two simple equations:
1) 100%=180
2) x%=483.6
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
100%/x%=180/483.6
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.
7. Solution for 483.6 is what percent of 180
100%/x%=180/483.6
(100/x)*x=(180/483.6)*x - we multiply both sides of the equation by x
100=0.37220843672457*x - we divide both sides of the equation by (0.37220843672457) to get x
100/0.37220843672457=x
268.66666666667=x
x=268.66666666667
now we have:
483.6 is 268.66666666667% of 180
Answer:
Around 0.73% of adults in the USA have stage 2 high blood pressure
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 121 and standard deviation of 16.
This means that 
Around what percentage of adults in the USA have stage 2 high blood pressure
The proportion is 1 subtracted by the p-value of Z when X = 160. So
has a p-value of 0.9927.
1 - 0.9927 = 0.0073
0.0073*100% = 0.73%
Around 0.73% of adults in the USA have stage 2 high blood pressure
Answer:
16
Step-by-step explanation:
