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Alina [70]
3 years ago
9

Find the area of each triangle.

Mathematics
2 answers:
lord [1]3 years ago
8 0
Hi there!

We can find the area of a triangle with the formula:
area = 0.5 \times base \times height

Filling in this formula gives us the following answers.

Triangle 1
area = 0.5 \times 5 \times 8 = 20

Triangle 2
area = 0.5 \times 7 \times 9 = 31.5

Triangle 3
area = 0.5 \times 16 \times 12 = 96
IrinaK [193]3 years ago
5 0
A=bh divided by 2!!

1. A=1/2(8)(5)
So A equals: 20.

2. A=1/2(9)(7)
So A equals: 31.5.

3. A=1/2(16)(12)
So A equals: 96.

Hope this helps!
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Jim is running on a trail that is 5/4 of a mile long. So far he has run 2/3 of the trail. How many miles has he run so far?
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Translate the phrase to an algebraic expression.
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Reptile [31]

See attachment for the graph of the hyperbola 12x^2 - 3y^2 - 108 = 0

<h3>How to graph the hyperbola?</h3>

The equation of the hyperbola is given as:

12x^2 - 3y^2 - 108 = 0

Start by calculating the transverse axis

So, we have:

<u>Transverse axis</u>

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

Where

a = 3 and b = 6

The transverse axis is calculated as:

y = ±b/a(x - h) + k

So, we have:

y = ±6/3(x - 0) + 0

Evaluate the difference and sum

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Evaluate the quotient

y = ±2x

This means that the transverse axes are y = 2x and y =-2x

<u>The vertices</u>

In the above section, we have:

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

<u>The co-vertices</u>

In the above section, we have:

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

And

a = 3 and b = 6

The co-vertices are

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So, we have:

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See attachment for the graph of the hyperbola

Read more about hyperbola at:

brainly.com/question/26250569

#SPJ1

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