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vovikov84 [41]
3 years ago
6

At a point on the ground 20 feet from a building, a surveyor observes the angle of inclination to the top of the building to be

pi/3 radians. How tall is the building?
Mathematics
1 answer:
Bess [88]3 years ago
8 0

Answer:

34.64 ft

Step-by-step explanation:

Distance from the building = 20 ft

Angle of inclination = π/3 radians

The tangent of the angle of inclination must equal the height of the building divided by the distance of the observer from the building:

tan( \pi/3) = \frac{h}{20} \\h = 20*1.73205\\h=34.64\ ft

The building is 34.64 ft tall

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Answer:

y = -6x + 10

Step-by-step explanation:

Parallel lines share the same slope.  Given y = -6x – 1, we know that the equation of this new line has the form y = -6x – C.  The coordinates of the point (1, 4) determine the value of C:

(4) = -6(1) – C, or:

4 = -6 - C

Then C = -10, and the desired equation is

y = -6x – (-10), or

y = -6x + 10

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Answer:

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Step-by-step explanation:

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2 years ago
the case of napkins contained 45 packs with a total of 10,125 napkins. each napkin contained the same number of napkins. write a
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You would need to do 10,125/45 = n, and in which case we just solve. 
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Hope this helps and have a nice day:)
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