Answer:
The box should have base 16ft by 16ft and height 8ft Therefore,dimensions are 16 ft by 16 ft by 8 ft
Step-by-step explanation:
We were given the volume of the tank as, 2048 cubic feet.
Form minimum weight, the surface area must be minimum.
Let the height be h and the lengths be x
the volume will be: V=x²h then substitute the value of volume, we have
2048=hx²
hence
h=2048/x²
Since the amount of material used is directly proportional to the surface area, then the material needs to be minimized by minimizing the surface area.
The surface area of the box described is
A=x²+4xh
Then substitute h into the Area equation we have
A= x² + 4x(2048/x²)
A= x² + 8192/x
We want to minimize
A
dA/dx = -8192/x² + 2 x= 0 for max or min
when dA/dx=0
dA/dx= 2x-8192/x²=0
2x=8192/x²
Hence
2x³=8192
x³=4096
x=₃√(4096)
X=16ft
Then h=2048/x²
h=2048/16²
h=8ft
The box should have base 16ft by 16ft and height 8ft
Hence the dimensions are 16 ft by 16 ft by 8 ft
The awnser to this question is 14.1
Answer:

Step-by-step explanation:
Given
Point: (6,3)
Required
Translate 2 units down and 3 units left
Taking the translation 1 after other
When a function is translated down, only the y axis is affected;
2 units down implies that, 2 be subtracted from the y value.
The function becomes


3 units right implies that, 3 be added tothe x value.
The function becomes


Hence;
Option D answers the question
The change in the stock market from the beginning of the day to the end of the day is 29 3/4
<h3>How to determine the change in the stock market from the beginning of the day to the end of the day?</h3>
The given parameters are:
Beginning = 60 3/4
End = 90 1/2
The change in the stock market from the beginning of the day to the end of the day is calculated as;
Change = End - Beginning
So, we have
Change = 90 1/2 - 60 3/4
Evaluate
Change = 29 3/4
Hence, the change in the stock market from the beginning of the day to the end of the day is 29 3/4
Read more about difference at:
brainly.com/question/17301989
#SPJ1
Answer:
t=6
Step-by-step explanation:
ground height = 0
(are you sure your formula is correct? isn't it - 16t²?)
if h=16t² +64t+192 is true then
16t² +64t+192 = 0
t² + 4t + 12 = 0
t = (-4 ± √(4² - 4*12)) / 2*1 = (-4 ± √-32) / 2 = -2 ± 2√-2
There is no solution of t
if it is h= - 16t² +64t+192
0 =- 16t² + 64t + 192
t² - 4t - 12 = 0
(t + 2) (t -6) = 0
t should be positive
t = 6 sec