Answer:
Here is the full question:
(A) If a closed container contains a mouse as well as enough food, water, and oxygen for the mouse to live for 3 weeks,
How much will the container weigh 1 and 2 weeks later after the mouse has eaten, drunk and exercised (respiration is CO2 emission), and why?
(B) If the mouse was in a wire cage and only the weights of the mouse, food, and water were considered, would you come to the same answer as in (A) and why?
Explanation:
(A) The mouse will weigh the same. This is because solids, liquid, and gases cannot escape the closed container. All of the life processes involving reactions conserve the atoms involved. Some of those atoms will appear in the form of gases, some as solids, and others as liquids but all will be retained in the closed container.
(B) In a wire cage, gases can escape. This means that the weight will not be the same after 1 and 2 weeks. The weight would be less than the original weight of the mouse, it's food, and it's water.
The plates will move and the underwater island will start to move and shift. It's possible it will also weather
I think it is that the cytoplam divides
Answer:
<em>The correct option is limited food and water resources favored the survival of smaller deer.</em>
Explanation:
The islands where the Key deer lived had limited food and water resources. As migration was not possible for these species because the white-tailed deer had more adaptations as compared to them, hence they had to somehow survive in these areas with limited food and water resources. Limited food resources were the reason that the Key deer could not grow properly and hence evolved to have very little weight.
Answer:
can you please rewrite that so it can make more sense
Explanation:
