Question

Find the equation of a line that contains the points (−5,−7) and (−8,0).

Answer 1

Answer:

$y=\frac{-7}{3}x-\frac{56}{3}$

Step-by-step explanation:

first find the slope using the slope formula

$slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$(x_{1},y_{1})=(-5,-7)$

$(x_{2},y_{2})=(-8,0)$

plug in

$\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{(0)-(-7)}{(-8)-(-5)}=\frac{0+7}{-8+5}=\frac{7}{-3}=\frac{-7}{3}$

m = -7/3

and using point slope form

$y-y_{1}=m(x-x_{1})$

$y-(-7)=(\frac{-7}{3})(x-(-5))$

$y+7=(\frac{-7}{3})(x+5)$

$y=\frac{-7}{3}x-\frac{35}{3}-7$

$y=\frac{-7}{3}x-\frac{35}{3}-\frac{21}{3}$

$y=\frac{-7}{3}x-\frac{56}{3}$