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2 years ago

Line WX is tangent to circle T at point X. Line WT intersects the circle at points P and Q. The radius of circle T is 12 units a

nd WP = 8 units. What is WX?

Mathematics

1 answer:

Anastasy [175]2 years ago

5 0

$PQ=2PT=2 \times 12=24\Rightarrow QW=PQ+PW=24+8=32 \\ \hat{W} \: is \: shared, \widehat{PXW}=\widehat{WQX}\Rightarrow \bigtriangleup PWX\cong \bigtriangleup XWQ \\ \Rightarrow \frac{WX}{QW} = \frac{PW}{WX} \\ \Rightarrow {WX}^{2} = PW.QW = 8 \times 24 = 192\Rightarrow WX = \sqrt{192} = 8 \sqrt{3}\: units$

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3 years ago

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Answer:

A, C, E

Step-by-step explanation:

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2 years ago

How do you solve (Arc)QPT if <QZT = 120

yuradex [85]

By definition, the arc length is given by:
arc = R * theta * ((2 * pi) / 360)
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We have then:
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Substituting values we have:
(Arc) QPT = R * theta * ((2 * pi) / 360)
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Answer:
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3 years ago

Mr. Brown owned a house, which he rented for $60 a month. The house was assessed at $9000. In 1975 the rate of taxation was incr

Alexandra [31]

We first calculate the percentage increase on the tax

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The amount of yearly rent would be then increased by 12%

Monthly rent = $60
Yearly rent = 60×12 = $720
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2 years ago

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tia_tia [17]

Answer:

i: the domain.

iii: the axis of symmetry.

Step-by-step explanation:

We have the function:

f(x) = x^2

The domain of this function is the set of all real numbers, and the range is:

R: [0, ∞)

(because 0 is the minimum of x^2)

Now we have the transformation:

d(x) = f(x) + 9 = x^2 + 9

Notice that this is only a vertical translation of 9 units, then there is no horizontal movement, then the axis of symmetry does not change.

Also, in d(x) there is no value of x that makes a problem, so the domain is the set of all real numbers, then the domain does not change.

And d(x) = x^2 + 9 has the minimum at x = 0, then the minimum is:

d(0) = 0^2 + 9 = 9

Then the range is:

R: [9, ∞)

Then the range changes.

So we can conclude that the attributes that will be the same for f(x) and d(x) are:

i: the domain.

iii: the axis of symmetry.

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2 years ago