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aleksandrvk [35]
3 years ago
9

Which type of navigation involves multiple frames that are linked to a number of other frames?

Computers and Technology
1 answer:
sesenic [268]3 years ago
8 0

Answer:

1. b)

2. c)

3. c)

4. a)

5. b)

Explanation:

1. and 5. Linear kind of navigation is a system with a sequential manner web pages that are perfect for some sorts of sites that are having information that has to be viewed as a book (5) and when we are talking about that view we are considering one page after another page like we are reading a book. It is also the simplest navigation. This is the explanation for question 1 and question 5.

2. The most well-designed navigation system is an intuitive one because in this design of the website we have website traffic that is easy because it flows from one web page to another web page. It is showing us where to go to find and look for something and even where to go if there is no concrete options for what are we looking for.

3. A Sitemap is referring to the organized hierarchy of links and it is the protocol that is allowing us to search through many links. A Sitemap is having a listing of the URLs for some site and that is why this is the correct answer.

4. In using liner reciprocal navigation the interface should include how frames are left and how many of them are there. The more the frames, the more times the user will spend on them and the site.

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Write a program that lets the user enter the total rainfall for each of 12 months (starting with January) into an array of doubl
lianna [129]

Answer:

The C++ code is given below with appropriate comments

Explanation:

#include "stdafx.h"

//Header file section

#include <iostream>

#include <iomanip>

#include <string>

using namespace std;

//Function prototypes

double rainfallTotal(double[], int);

double averageMonthlyRainfall(double[], int);

double highestAmountRainfall(double[], int, int &);

double lowestAmountRainfall(double[], int, int &);

int main()

{

//Initialize variables

const int ALL_MONTHS = 12;

int highIndex = 0;

int lowIndex = 0;

//Declare variables

double totalRf;

double averageRf;

double mostRf;

double leastRf;

double monthlyRf[ALL_MONTHS];

string monthName[ALL_MONTHS] = { "January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December" };

for (int i = 0; i < ALL_MONTHS; i++)

{

 cout << "Enter rainfall for " << monthName[i] << ": ";

 cin >> monthlyRf[i];

 // Check the input as negative numbers

 //for monthly rainfall

 while (monthlyRf[i] < 0)

 {

  cout << "Invalid data (negative rainfall) " << endl;

  cout << "Retry the rainfall in " << monthName[i] << ": ";

  cin >> monthlyRf[i];

 }

}

//Call the methods

totalRf = rainfallTotal(monthlyRf, ALL_MONTHS);

averageRf = averageMonthlyRainfall(monthlyRf, ALL_MONTHS);

mostRf = highestAmountRainfall(monthlyRf, ALL_MONTHS, highIndex);

leastRf = lowestAmountRainfall(monthlyRf, ALL_MONTHS, lowIndex);

//Display output

cout << fixed << showpoint << setprecision(2) << endl;

cout << "Total rainfall: " << totalRf << endl;

cout << "Average rainfall: " << averageRf << endl;

cout << "Least rainfall in " << monthName[lowIndex] <<endl;

cout << "Most rainfall in " << monthName[highIndex] <<endl;

system("pause");

return 0;

}

//Method definition of rainfallTotal

double rainfallTotal(double totalRainfall[], int n)

{

double total = 0;

for (int i = 0; i < n; i++)

 total += totalRainfall[i];

return total;

}

//Method definition of averageMonthlyRainfall

double averageMonthlyRainfall(double totalRainfall[], int n)

{

double average = 0.0;

double total = 0;

for (int i = 0; i < n; i++)

 total += totalRainfall[i];

average = total / n;

return average;

}

//Method definition of lowestAmountRainfall

double lowestAmountRainfall(double totalRainfall[], int n, int &monthIndex)

{

double least;

int i = 0;

least = totalRainfall[i];

while (i < n)

{

 if (totalRainfall[i] < least)

 {

  least = totalRainfall[i];

  monthIndex = i;

 }

 i++;

}

return least;

}

//Method definition of highestAmountRainfall

double highestAmountRainfall(double totalRainfall[], int n, int &monthIndex)

{

double high;

int i = 0;

high = totalRainfall[i];

while (i < n)

{

 if (totalRainfall[i] > high)

 {

  high = totalRainfall[i];

  monthIndex = i;

 }

 i++;

}

return high;

}

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When Britain forbade the sale of cotton to the Central Powers, how did it deal with U.S. cotton trading
tresset_1 [31]

Britain deal with U.S. cotton trading by  purchasing American cotton surplus.

<h3>Who were the Central Powers ?</h3>

The Central Powers can be referred to as the Central Empires, and they serves as the part of coalitions who fought World War I, they comprises German Empire, Austria-Hungary and others.

Britain Britain forbade the sale of cotton to the Central Powers, and that's why they do buy in surplus from United States.

Learn more about Central Powers,  at;

brainly.com/question/651584

4 0
2 years ago
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