Answer:
Yes, we can conclude that the population standard deviation of TV watching times for teenagers is less than 2.66
Step-by-step explanation:
H0 : σ² = 2.66²
H1 : σ² < 2.66²
X²c = (n - 1)*s² ÷ σ²
sample size, n = 40
Sample standard deviation, s = 1.9
X²c = ((40 - 1) * 1.9²) ÷ 2.66²
X²c = 140.79 ÷ 7.0756
X²c = 19.897
Using a confidence level of 95%
Degree of freedom, df = n - 1 ; df = 40 - 1 = 39
The critical value using the chi distribution table is 25.6954
Comparing the test statistic with the critical value :
19.897 < 25.6954
Test statistic < Critical value ; Reject the Null
Hence, we can conclude that the population standard deviation of TV watching times for teenagers is less than 2.66
That would be 18 yards.
Since 3 feet equals 1 yard, you must divide 54 by 3 and you get 18.
Did You Figure This Out I Need Help Too. Lol
The difference between the y-coordinates is 7 units. If the area is to be 42 square units, the missing coordinates must be 42/7 = 6 units to the right of those shown.
B = A +(6, 0) = (-4, 4) +(6, 0) = (-2, 4)
D = C +(6, 0) = (-4, -3) +(6, 0) = (-2, -3)
The appropriate choice is the last one, ...
(-2, 4) and (-2, -3)
The answer should come up to n+11=2.