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3 years ago

When ∆RST is translated 4 units down, what are the apparent coordinates of T’?

Mathematics

1 answer:

Klio2033 [76]3 years ago

4 0

Answer:

T' is at (-1,-8)

Step-by-step explanation:

When we translate down 4 units, we will subtract 4 from the y coordinate

T is at (-1,-4)

We need to subtract 4 from the y coordinate

T' is at (-1,-4-4)

T' is at (-1,-8)

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three students ordered wings that cost $21 and french fries for 6$. If they split the bill equally how much did each student pay

SVEN [57.7K]

The total is $21 + $6 or $27.

There are 3 students.

Let p = how much each student will pay

p = $27 ÷ 3 students

p = $9

Each student will pay $9.

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3 years ago

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M=0.75d - 2 proportional or non proportional?

ArbitrLikvidat [17]

Answer:

Non proportional

Step-by-step explanation:

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3 years ago

Jeremy is the oldest of four brothers. Each of the four boys gets an allowance for doing chores at home each week. The amount of

frez [133]

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3 years ago

Simplify a+a+a= 4b-b 3x2+x2

Reika [66]

<h2>Good morning,</h2>

__________________

Answer:

a+a+a = 3a.

4b-b = 3b.

3x²+x² = 4x².

explanation

a+a+a = 3a.

4b-b = b(4 - 1) = b × 3 = 3b.

3x²+x² = x²(3 + 1) = x² × 4 = 4x².

_______________________________

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4 years ago

Determine the measure of each segment then indicate whether the statements are true or false

kupik [55]

Answer:

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

A(-4, 4)

B(2, 5)

Finding the length of AB using the formula

$d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}$

$=\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}$

$=\sqrt{6^2+1}$

$=\sqrt{36+1}$

$=\sqrt{37}$

$d_{AB}\:=\sqrt{37}$

$d_{AB}=6.08$ units

Given the vertices of the segment JK

J(2, 2)

K(7, 2)

From the graph, it is clear that the length of JK = 5 units

$d_{JK}=5$ units

Given the vertices of the segment GH

G(-5, -2)

H(-2, -2)

Finding the length of GH using the formula

$d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}$

$=\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}$

$=\sqrt{3^2+0}$

$=\sqrt{3^2}$

$\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$d_{GH}\:=\:3$ units

Thus, from the calculations, it is clear that:

$d_{AB}=6.08$

$d_{JK}=5$

$d_{GH}\:=\:3$

Thus,

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

8 0

3 years ago