The answer for this problem would be:
Orbital period if distance = 128,000,00 km and mass = Sun?
<span>This is approximately be .85 astronomical units if converted km to au.
</span>
We will be using Kepler's third law which is:
<span>T^2 = r^3 </span>
<span>T^2 = .85^3 </span>
<span>T^2 = .61
</span>
get the square root of .61
so the answer will be:
<span>T = .78 Years which is in months is 9.36 months.</span>
Answer:a
Step-by-step explanation:
Answer:
6 apples because
Step-by-step explanation:
12÷2=6
Answer:
v = 0.58
Step-by-step explanation:
-22 - 7v = -3(8v + 4)
Expand -3(8v + 4)
3 * 8v - 3 * 4
Simplify -3 * 8v -3 * 4
= -24v - 12
-22 - 7v = -24v - 12
Add 22 to both sides
-7v = -24v +10
Add 24v to both sides
17v = 10


