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vazorg [7]
4 years ago
6

The blue dot is what value on the number line

Mathematics
2 answers:
anzhelika [568]4 years ago
8 0
Go up by 2 each time. answer is 20
Degger [83]4 years ago
8 0
20 hope this helps! it goes up by 2
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Answer

He should've drawn the arrow starting from -15 pointing right to show how adding these two numbers would equal zero... hope this helped

Step-by-step explanation:

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What was Fibonacci vision for the world? What did Fibonacci hope the world would be like?
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which inequality can represent the situation? "You are saving money for a summer camp that cost $1800. You have saved $500 so fa
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Please help asap, will give brainiest. TY! :3
lilavasa [31]

Answer:

Page 1::1 & 3 & 4

Page 2:6

Page 3:8/1

Page 4:15 3/4

Step-by-step explanation:

HOPE THIS HELPS!!

8 0
3 years ago
Worth 25 points!
MrRissso [65]

Answer:

1) \sqrt{-48}=4\sqrt{3} \ i

2) \sqrt{-63}=3\sqrt{7} \ i

3) \sqrt{-72}=6\sqrt{2} \ i

4) \sqrt{-24}=4\sqrt{6} \ i

5) \sqrt{-84}=2\sqrt{21} \ i

6) \sqrt{-99}=3\sqrt{11} \ i

Step-by-step explanation:

We need to simply the following :

<u>Note: For all questions given we know that </u>\sqrt{-1}=i<u> using it in all the given questions.</u>

1) \sqrt{-48}

Factors of 48 are: 2x2x2x2x3

\sqrt{-48}\\=\sqrt{48}\sqrt{-1}  \\=\sqrt{2\times2\times2\times2\times3}\ i\\=  \sqrt{2^2\times2^2\times3}\ i\\=2\times2\sqrt{3} \ i \\=4\sqrt{3} \ i

2) \sqrt{-63}

Factors of 63 are: 3x3x7

\sqrt{-63}\\=\sqrt{63}\sqrt{-1}  \\=\sqrt{3\times3\times7}\ i\\=  \sqrt{3^2\times7}\ i\\=3\sqrt{7} \ i

3) \sqrt{-72}

Factors of 72 are: 2x2x2x3x3

\sqrt{-72}\\=\sqrt{72}\sqrt{-1}  \\=\sqrt{2\times2\times2\times3\times3}\ i\\=  \sqrt{2^2\times3^2\times2}\ i\\=2\times3\sqrt{2} \ i \\=6\sqrt{2} \ i

4) \sqrt{-24}

Factors of 24 are: 2x2x2x3

\sqrt{-24}\\=\sqrt{24}\sqrt{-1}  \\=\sqrt{2\times2\times2\times3}\ i\\=  \sqrt{2^2\times2\times3}\ i\\=2\sqrt{2\times3} \ i \\=2\sqrt{6} \ i

5) \sqrt{-84}

Factors of 84 are: 2x2x3x7

\sqrt{-84}\\=\sqrt{84}\sqrt{-1}  \\=\sqrt{2\times2\times3\times7}\ i\\=  \sqrt{2^2\times3\times7}\ i\\=2\sqrt{21} \ i

6) \sqrt{-99}\\

Prime factors of 99 are: 3x3x11

\sqrt{-99}\\=\sqrt{99}\sqrt{-1}  \\=\sqrt{3\times3\times11}\ i\\=  \sqrt{3^2\times11}\ i\\=3\sqrt{11} \ i \\=3\sqrt{11} \ i

6 0
3 years ago
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