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TEA [102]
3 years ago
11

How do I solve this problem? I don’t know the answer I just need to know how to solve

Mathematics
1 answer:
Vikki [24]3 years ago
8 0

(18x + 36)/2 = -24

Do the opposite of PEMDAS. Note the equal sign. What you do to one side you do to the other. Isolate the x.

First multiply 2 to both sides

(18x + 36)/2(2) = -24(2)

18x + 36 = -24(2)

18x + 36 = -48

Isolate the x. Subtract 36 from both sides

18x + 36 (-36) = - 48 (-36)

18x = -48 - 36

18x = - 84

Isolate the x, divide 18 from both sides

18x/18 = -84/18

x = -84/18

x = -4.67 (rounded)

-4.67 rounded should be your answer

hope this helps

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I need help please! I've been stuck on this for a week and its really stressful lol
worty [1.4K]

Answer:

y=0.2*4^{x}

Step-by-step explanation:

Notice when x increases 1, y is 4 times the previous one, so

the function is like y=C*4^{x}

To determine the constant C, put any pair of (x, y)

Use x = 0, y = 0.2, so

0.2 = C*4^{0} = C * 1 = C

then y=0.2*4^{x}

5 0
2 years ago
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An object is moving at a speed of 6 miles per month. Express this speed in feet per hour
patriot [66]

Answer:

44 feet/hour

Step-by-step explanation:

6mi/month(5280ft/1mi)(1month/30days)(1day/24hrs)

Assuming the month has 30 days, object moves at 44 feet/hour. You want all the units to cancel till you get the ones you need, in this case feet/hr.

7 0
3 years ago
Axis of sym: x =
marta [7]

Answer:

<h2>SEE BELOW</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • quadratic function
  • PEMDAS
<h3>let's solve:</h3>

vertex:(h,k)

therefore

vertex:(-1,4)

axis of symmetry:x=h

therefore

axis of symmetry:x=-1

  • to find the quadratic equation we need to figure out the vertex form of quadratic equation and then simply it to standard form i.e ax²+bx+c=0

vertex form of quadratic equation:

  • y=a(x-h)²+k

therefore

  • y=a(x-(-1))²+4
  • y=a(x+1)²+4

it's to notice that we don't know what a is

therefore we have to figure it out

the graph crosses y-asix at (0,3) coordinates

so,

3=a(0+1)²+4

simplify parentheses:

3 = a(1 {)}^{2}  + 4

simplify exponent:

3 =  a + 4

therefore

a =  - 1

our vertex form of quadratic equation is

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let's simplify it to standard form

simplify square:

y =  - ( {x}^{2}  + 2x + 1)  + 4

simplify parentheses:

y =  -  {x}^{2}  - 2x - 1 + 4

simplify addition:

y =  -  {x}^{2}  - 2x + 3

therefore our answer is D)y=-x²-2x+3

the domain of the function

x\in \mathbb{R}

and the range of the function is

y\leqslant 4

zeroes of the function:

-  {x}^{2}  - 2x + 3 = 0

\sf divide \: both \: sides \: by \:  - 1

{x}^{2}  + 2x - 3 = 0

\implies \:  {x}^{2} +   3x  - x  +  3 = 0

factor out x and -1 respectively:

\sf \implies \: x(x + 3)   - 1(x  + 3 )= 0

group:

\implies \: (x - 1)(x + 3) = 0

therefore

\begin{cases} x_{1} = 1 \\  x_{2}  =  - 3\end{cases}

4 0
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mel-nik [20]
The answer should be True!

Hope it helped you.


-Charlie

:)
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